a2 + b2 = c2. 62 + 82=c2. 36+64=c2. 100=c2. sqrt(100)=sqrt(c2). c=10. So the diagonal is 10 m. long.
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
The dimensions are 27cm by 36 cm, solved with the help of Pythagoras' theorem
60 feet Solved with the help of Pythagoras' theorem
The length is (18 centimeters) minus (the width)
43.26661530556787
The diagonal is 45.61 feet.
(Diagonal)2 = (36)2 + (26)2 = 1,972Diagonal = sqrt(1,972) = 44.4072 (rounded)
Perimeter = 25+36+25+36 = 122 units of measurement Use Pythagoras' theorem to find the other side of the rectangle
Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal
a2 + b2 = c2. 62 + 82=c2. 36+64=c2. 100=c2. sqrt(100)=sqrt(c2). c=10. So the diagonal is 10 m. long.
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
Using Pythagoras its base works out as 36 and so 36*15 = 540 square units
The dimensions are 27cm by 36 cm, solved with the help of Pythagoras' theorem
60 feet Solved with the help of Pythagoras' theorem
18