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How long is the diagonal of a rectangle with dimensions 6M by 8M?
a2 + b2 = c2. 62 + 82=c2. 36+64=c2. 100=c2. sqrt(100)=sqrt(c2). c=10. So the diagonal is 10 m. long.
What is the diagonal measurement of a 36' by 56' rectangle?
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
What is the width of a rectangle if its diagonal is 45 cm?
The dimensions are 27cm by 36 cm, solved with the help of Pythagoras' theorem
What is length of diagonal line in a rectangle 48 feet by 36 feet?
60 feet Solved with the help of Pythagoras' theorem
What is the length of a rectangle if the perimeter is 36 centimeters?
The length is (18 centimeters) minus (the width)
How long is a diagonal of a 24 ft x 36 ft rectangle?
43.26661530556787
What is the diagonal measurement of a rectangle measuring 36 feet by 28 feet?
The diagonal is 45.61 feet.
What is the diagonal measurement of a rectangle 36 ft x 26 ft?
(Diagonal)2 = (36)2 + (26)2 = 1,972Diagonal = sqrt(1,972) = 44.4072 (rounded)
What is the perimeter of a rectangle with a diagonal of 39 and a side of 36?
Perimeter = 25+36+25+36 = 122 units of measurement Use Pythagoras' theorem to find the other side of the rectangle
What is length of diagonal line in rectangle 32 feet by 36 feet?
Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal
How long is the diagonal of a rectangle with dimensions 6M by 8M?
a2 + b2 = c2. 62 + 82=c2. 36+64=c2. 100=c2. sqrt(100)=sqrt(c2). c=10. So the diagonal is 10 m. long.
What is the diagonal measurement of a 36' by 56' rectangle?
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
What is the diagonal measurement of a square 24 feet x 36 feet?
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
What is the width of a rectangle if its diagonal is 45 cm?
The dimensions are 27cm by 36 cm, solved with the help of Pythagoras' theorem
What is the area of a rectangle with a diagonal of 39 and a height of 15?
Using Pythagoras its base works out as 36 and so 36*15 = 540 square units
What is length of diagonal line in a rectangle 48 feet by 36 feet?
60 feet Solved with the help of Pythagoras' theorem
If LMNO is a rectangle and MO equals 36 what is the length of?
18
