(Diagonal)2 = (36)2 + (26)2 = 1,972
Diagonal = sqrt(1,972) = 44.4072 (rounded)
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal
Since a square has right angles, you can use the Pythagorean Theorem to calculate the diagonal. Specifically, the diagonal of a square is equal to the length of a side, multiplied by the square root of 2.
about 36'
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
The diagonal is 45.61 feet.
Perimeter = 25+36+25+36 = 122 units of measurement Use Pythagoras' theorem to find the other side of the rectangle
The diagonal measurement for 36 feet by 36 feet is 50.91 feet.
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
The diagonal of a 36 x 36 foot square is 50.91 feet.
43.26661530556787
A Square 28 by 36 - surely that is a rectangle Use Pythagoras' theorem: 282+362 = 2080 and the square root of this number is 45.607017 or about 46 units
Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal
36-26-36
If it was a square, which is a rectangle, the perimeter would be 24 meters . But it was a regular rectangle than it could be a few things actually , one of them would be 26 meters . Another would be 40 meters I think .
The dimensions are 27cm by 36 cm, solved with the help of Pythagoras' theorem