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There are 900 3-digit numbers, 100 to 999.
The 3 may be in the hundreds place, the tens place, or the ones.
The numbers 300 - 399 have 3 in the hundreds place.
The numbers 130, 131 ... 938, 939 have 3 in the tens place.
The numbers 103, 113, 123 ... 993 have 3 in the ones place.
That would total 100 + 90 + 90 = 280 except that now we have double counted some numbers with 2 or more threes in them. I believe if you count carefully you will find 19 double counted numbers in the 300 - 399 group and 8 numbers with the tens digit and ones digit equal to 3. Lastly, the number 333 was triple counted. 280 - 28 = 252. There are several ways to solve this problem. I encourage you to double-check my results ... who is to say this is correct?
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How many three digit numbers have odd prime number as 1st digit A prime number as 2nd digit and an odd number as 3rd digit?
There are 17 such numbers.
How many 3 digit numbers contain the digit 2 at least once?
252
How many 3 digit numbers are there that contain at least 1 seven?
252
How many 3-digit numbers are there using 2 4 6 8 and 9?
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
How many numbers does a creditcard number have?
A credit card number is a 16 digit number.
How many seven digit numbers contain the number seven at least once?
To find the total number of seven-digit numbers that contain the number seven at least once, we can use the principle of complementary counting. There are a total of 9,999,999 seven-digit numbers in total. To find the number of seven-digit numbers that do not contain the number seven, we can count the number of choices for each digit (excluding seven), which is 9 choices for each digit. Therefore, there are 9^7 seven-digit numbers that do not contain the number seven. Subtracting this from the total number of seven-digit numbers gives us the number of seven-digit numbers that contain the number seven at least once.
How many three digit numbers have odd prime number as 1st digit A prime number as 2nd digit and an odd number as 3rd digit?
There are 17 such numbers.
How many 3 digit numbers contain the digit 2 at least once?
252
How many numbers are there between 100000 and 125000 where the numbers are only used once and are in order of least to greatest?
theres only 1 number which is 123456, the least digit is 1 and the greatest is 6
How many 5 digit combos in 30 numbers?
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
How many numbers are in a routing number?
Routing number is 9 digit number.
How many thousands are there in Ten Thousands?
There are 9000 4 digit numbers Find 4 digit numbers that are all different from 1 find 4 digit numbers that are all different from 1 The thousands digit has 8 ways to choose, hundreds, tens, and units all have 9 ways => there are 8 x 9 x 9 x 9 = 5832 digits => 4 digit numbers contain at least 1 digit 1 = number of 4 digit numbers , the number of 4 digit numbers is different by digit 1 =9000 - 5832 = 3168 numbers
How many numbers are between 100000 and 125000 where the digits are in order from least to greatest no digit can be repeated?
There is only one number and that is 123456.
If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
How many 3 digit numbers are there that contain at least 1 seven?
252
How many three digit numbers exist in which the last digit is the same as the last digit of that number squared?
300
How many 3-digit numbers are there using 2 4 6 8 and 9?
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
