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There are 900 3-digit numbers, 100 to 999.
The 3 may be in the hundreds place, the tens place, or the ones.
The numbers 300 - 399 have 3 in the hundreds place.
The numbers 130, 131 ... 938, 939 have 3 in the tens place.
The numbers 103, 113, 123 ... 993 have 3 in the ones place.
That would total 100 + 90 + 90 = 280 except that now we have double counted some numbers with 2 or more threes in them. I believe if you count carefully you will find 19 double counted numbers in the 300 - 399 group and 8 numbers with the tens digit and ones digit equal to 3. Lastly, the number 333 was triple counted. 280 - 28 = 252. There are several ways to solve this problem. I encourage you to double-check my results ... who is to say this is correct?
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How many three digit numbers have odd prime number as 1st digit A prime number as 2nd digit and an odd number as 3rd digit?
There are 17 such numbers.
How many 3 digit numbers contain the digit 2 at least once?
252
How many 3 digit numbers are there that contain at least 1 seven?
252
How many 3-digit numbers are there using 2 4 6 8 and 9?
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
How many times does the digit 9 appear in the whole numbers at least once?
Infinitely many.
How many seven digit numbers contain the number seven at least once?
To find the total number of seven-digit numbers that contain the number seven at least once, we can use the principle of complementary counting. There are a total of 9,999,999 seven-digit numbers in total. To find the number of seven-digit numbers that do not contain the number seven, we can count the number of choices for each digit (excluding seven), which is 9 choices for each digit. Therefore, there are 9^7 seven-digit numbers that do not contain the number seven. Subtracting this from the total number of seven-digit numbers gives us the number of seven-digit numbers that contain the number seven at least once.
How many three digit numbers have odd prime number as 1st digit A prime number as 2nd digit and an odd number as 3rd digit?
There are 17 such numbers.
How many 3 digit numbers contain the digit 2 at least once?
252
How many numbers are there between 100000 and 125000 where the numbers are only used once and are in order of least to greatest?
theres only 1 number which is 123456, the least digit is 1 and the greatest is 6
How many 5 digit combos in 30 numbers?
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
How many numbers are in a routing number?
Routing number is 9 digit number.
How many thousands are there in Ten Thousands?
There are 9000 4 digit numbers Find 4 digit numbers that are all different from 1 find 4 digit numbers that are all different from 1 The thousands digit has 8 ways to choose, hundreds, tens, and units all have 9 ways => there are 8 x 9 x 9 x 9 = 5832 digits => 4 digit numbers contain at least 1 digit 1 = number of 4 digit numbers , the number of 4 digit numbers is different by digit 1 =9000 - 5832 = 3168 numbers
If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
How many 3 digit numbers are there that contain at least 1 seven?
252
How many three digit numbers exist in which the last digit is the same as the last digit of that number squared?
300
How many 3-digit numbers are there using 2 4 6 8 and 9?
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
How many 3-digit palindromic numbers are there?
To be a 3 digit palindromic number, it must be of the form aba.I assume that a 3 digit number must be at least 100 (so that 020 for example does not count as a 3 digit number):a can be any of the nine digits 1-9;for each of these b can be any of the ten digits 0-9Thus there are 9 x 10 = 90 three digit palindromic numbers.
