Best Answer

WRONG ANSWER NB !!If repeated numbers are permitted the answer is 8x8x8x8x8=32768 (85)

If the numbers can only be used once in each combination, the answer is 8x7x6x5x4= 6720, where ABCDE has [n!/ (n-r)!] or [8! / 3!] combinations for 8 numbers used 5 at a time.

NONONO

NO THIS IS NOT THE RIGHT FORMULA IT SHD BE [n ! / (n-r)! x r! ] = ONLY 56 COMBINATIONS where each number can only be used once.

8x7x6x5x4x3x2x1 / (3x2x1) ( 5x4x3x2x1) = 56

from napoleon solo

Q: How many 5 digit combinations can you make with 8 numbers?

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5

45.

There are 5*4*3*2 = 120 such numbers.

Just one. In a combination, the order of the digits does not matter.

106 or a million.

Related questions

Number of 7 digit combinations out of the 10 one-digit numbers = 120.

90

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.

There are 1140 five digit combinations between numbers 1 and 20.

There are 840 4-digit combinations without repeating any digit in the combinations.

You would get 4!/2! = 12 combinations.

7

56 combinations. :)

Any 6 from 51 = 18,009,460 combinations

5

45.

There are 5*4*3*2 = 120 such numbers.