The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
How many two digit number are divisible by 5
The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2. 5
There are 5! = 120 such numbers.
There are 5460 five digit numbers with a digit sum of 22.
5
84
There are 600 5-digit numbers divisible by 150.
There are five such numbers.
With a total of 90,000 five digit numbers, we can conclude that there is 45,000 EVEN five digit numbers.
There are 9000 of them.
None. 3 digit numbers are not divisible by 19 digit numbers.
There are 90000 5-digit numbers.
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
120
4
There are 9000 4-digit numbers. 8*9*9*9 = 5832 of them do not contain a 5 The remaining 3168 contain a 5.