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Assuming all 9 numbers are one digit and different

1st number can be any of the 9 numbers

2nd any of the remaining 8 numbers

3rd any of the remaining 7 numbers

4th any of the remaining 6 numbers

5th any of the remaining 5 numbers

So total is 9 x 8 x 7 x 6 x 5 = 15,120 combinations

* * * * *

That is the number of permutations, not combinations.

In the above method, 12345, 12354, 12435, etc would all be counted as different even though they are all the SAMEcombination of numbers. Thus there are 120

The correct answer is 9C5 = 9*8*7*6*5/(5*4*3*2*1) = 126 combinations.

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Q: How many 5 number combinations can you make from 9 numbers?
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