There are 120 permutations and 5 combinations.
60 choices The way you get this answer is 5 times 4 times 3 if there are no repeats. That is mathematically speaking the number of Permutations of 3 from 5. The number of mathematical Combinations (where order doesn't matter, ie groupings) of 3 from 5 is 10.
654321-100000= 554321 combinations
There are 5,461,512 such combinations.
1
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 120 permutations and 5 combinations.
The number of combinations is nCr = (59*58*57*56*55)/(5*4*3*2*1) = 5006386
There are 7C4 = 7!/(4!*3!) = 7*6*5/(3*2*1) = 35 combinations.
60 choices The way you get this answer is 5 times 4 times 3 if there are no repeats. That is mathematically speaking the number of Permutations of 3 from 5. The number of mathematical Combinations (where order doesn't matter, ie groupings) of 3 from 5 is 10.
There is 345, 354, 435, 453, 543, 534.
654321-100000= 554321 combinations
Assuming a number can appear only once, there are 47C5 = 47*46*45*44*43/(5*4*3*2*1) = 1,533,939 combinations.
There are 5,461,512 such combinations.
just intrested in the number combinations * * * * * Number of combinations = 56C6 = 56*55*54*53*52*51/(6*5*4*3*2*1) = 32,468,436
The rearrangement of 5 figure numbers will be 5x4x3x2x1 which is 120 combinations, when you don't repeat a number.
There are 11,238,513 of them.