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This is just the combination formula (nCr) found in a statistics book:
27!/5!(27-5)! ! stands for factorial .
so 27! = 10888869450418352160768000000
and 5!=120
and 22!=1124000727777607680000
ans=80730
note you would hardly ever write the factorial answers out, instead just hit the n! button on your calculator to get a factorial of a number i.e to get 27! just type 27 then n!.
What else can I help you with?
How many combinations of 5 in 8?
27
How many 2 letter combinations are there?
27^27
What number combinations can be made with the numbers 1 2 3 4 5 6 7?
There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.
How many different combinations of 5 bills and 2 bills can be used to make a total of 27?
To find the combinations of 5 bills and 2 bills that sum to 27, we can denote the number of 5-dollar bills as (x) and the number of 2-dollar bills as (y). The equation we need to solve is (5x + 2y = 27) with the constraints (x \geq 0) and (y \geq 0). By testing non-negative integer values for (x), we find that possible combinations are ( (5, 1), (4, 3), (3, 5), (2, 7), (1, 9), (0, 13) ), resulting in a total of 6 combinations.
How many answers are there for a 3 digit keypad?
There are 27 possible combinations.
How many combinations of 5 in 8?
27
How many 2 letter combinations are there?
27^27
What number combinations can be made with the numbers 1 2 3 4 5 6 7?
There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.
How many combinations of 5 numbers are in 1 through 31?
31C5 which is 31!/[5!*(31-5)!] = 31*30*29*28*27/(5*4*3*2*1) = 169911
How many answers are there for a 3 digit keypad?
There are 27 possible combinations.
How many combinations of 3 books out of 5?
There are 5C3 = 5*4/(2*1) = 10 combinations
How many 5 digit number combinations from 1 to 60slide1?
There are 5,461,512 such combinations.
How many 3 item combinations are there if you have 5 items?
There are 5C3 = 10 combinations.
How many different possible combinations of coins are there in 27 cents?
To determine the number of different combinations of coins that make up 27 cents, we can use pennies (1 cent), nickels (5 cents), dimes (10 cents), and quarters (25 cents). A systematic approach or generating functions can be employed, but an approximate method indicates that there are 13 combinations using these coins. The combinations include various configurations of each coin type to total 27 cents.
How many combinations of 2 breads with or without lettuce and 5 toppings?
There are 2*2*5 = 20 combinations.
How many different symetry combinations can you find in a 3 by 3 square?
27
How many combinations can you make with the numbers 2 3 6 7 and 8?
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
