There are 7 choices for the first place. That leaves 6 choices for the second place and that leaves 5 choices for the third place.
So seven times six times five is 210 This assumes each number can only be used once.
Now lotteries where the player chooses numbers, say, six numbers out of 40, usually arrange the numbers in ascending order so a lot of combinations are eliminated.
For example, 123, 231, 321, 312, 132,213 are all possible combinations of three digits but to the lottery machine they are all the same as 123
In lotteries where a number is preprinted on the ticket, that number retains its original order so 123 is not the same as 213 or 321
Numbers games can be based on some unknown number like the number of letters in the headline of tomorrow`s newspaper.
what ever the game, the odds are usually against the player.
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There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
7 of them. Remember, that in a combination the order of the numbers does not matter.
10!/3! = 604800 different combinations.
Assuming you meant how many combinations can be formed by picking 8 numbers from 56 numbers, we have:(56 * 55 * 54 * 53 * 52 * 51 * 50 * 49)/8! = (7 * 11 * 3 * 53 * 13 * 51 * 25 * 7) = 1420494075 combinations. (Also equal to 57274321104000/40320)