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How many different 4 letter permutations are there for the letters in the word toolroom?
120 four letter permutations if you don't allow more than one 'o' in the four letter
arrangement.
209 four letter permutations if you allow two, three and all four 'o'.
1.- Let set A = {t,l,r,m,}, and set B = {o,o,o,o}.
2.- From set A, the number of 4 letter permutations is 4P4 = 24.
3.- 3 letters from set A give 4P3 = 24, and one 'o' can take 4 different positions in the
word. That gives us 24x4 = 96 four letter permutations.
4.- In total, 24 + 96 = 120 different four letter permutations.
5.- If the other three 'o' are allowed to play, then you have 2 letters from set A that
give 4P2 = 12 permutations and two 'o' can take 4C2 = 6 position's, giving 12x6 = 72
four letter permutations.
6.- One letter from set A we have 4P1 = 4, each one can take 4 different positions, the
rest of the spaces taken by three 'o' gives 4x4 = 16 different permutations.
7.- The four 'o' make only one permutation.
8.- So now we get 72 + 16 + 1 = 89 more arrangements adding to a total of 89 + 120 = 209 different 4 letter arrangements made from the letters of the word toolroom.
[ nCr = n!/((n-r)!∙r!); nPr = n!/(n-r)! ]
What else can I help you with?
How many different three letter permutations can be from the letter in the word clipboard?
There are 9 * 8 * 7, or 504, three letter permutations that can be made from the letters in the work CLIPBOARD.
How many different three letter permutations can be formed from the letters in the word clipboard?
There are three that I can see, there's clip, board and lip.
How many different 4-letter permutations can be formed from the letters in the word DECAGON?
The word "DECAGON" has 7 letters, with the letter "A" appearing once, "C" appearing once, "D" appearing once, "E" appearing once, "G" appearing once, "N" appearing once, and "O" appearing once. To find the number of different 4-letter permutations, we need to consider combinations of these letters. Since all letters are unique, the number of 4-letter permutations is calculated using the formula for permutations of n distinct objects taken r at a time: ( P(n, r) = \frac{n!}{(n-r)!} ). Here, ( n = 7 ) and ( r = 4 ), so the number of permutations is ( P(7, 4) = \frac{7!}{(7-4)!} = \frac{7!}{3!} = 7 \times 6 \times 5 \times 4 = 840 ). Thus, there are 840 different 4-letter permutations that can be formed from the letters in "DECAGON."
How many combination of 24 letters?
The answer can be written as "24!" or 24 factorial, which means 24 X 23 X 22 .... X 3 X 2 X1. The answer is 620,448,401,733,239,439,360,000 different combinations. --------------------------------------------------------------------------------------------- The question should say "permutations of 24 different letters" I believe, for which the above answer is. Number of 24 different letter permutations.
How many 5 letter permutations can be formed from the letters in vertical?
There are 8P5 = 8*7*6*5*4 = 6720
How many different four-letter permutations are there for the letters in the word toolroom?
loom, loot, molt, mool, moor, moot, mort, room, root, rotl, roto, tool, toom, toro
How many different 3 letter permutations can be formed from the letters in the word count?
There are 5*4*3 = 60 permutations.
How many different three letter permutations can be from the letter in the word clipboard?
There are 9 * 8 * 7, or 504, three letter permutations that can be made from the letters in the work CLIPBOARD.
What is the number of distinguishable permutations of the letters in the word oregon?
360. There are 6 letters, so there are 6! (=720) different permutations of 6 letters. However, since the two 'o's are indistinguishable, it is necessary to divide the total number of permutations by the number of permutations of the letter 'o's - 2! = 2 Thus 6! ÷ 2! = 360
How many permutations of 5 letter can be made without any letters being repeated?
There are 7893600 permutations.
How many different ways are there to to scramble to letters of the word mass if s needs to be the first letter?
The number of permutations of the letters MASS where S needs to be the first letter is the same as the number of permutations of the letters MAS, which is 3 factorial, or 6. SMAS SMSA SAMS SASM SSMA SSAM
What is the number of two letter permutations of the letters rib?
Six.
How many distinguishable 5-letter combinations are possible of the letters of the word tight?
Normally, there would be 5!=120 different permutations* of five letters. Since two of the letters are the same, we can each of these permutations will be duplicated once (with the matching letters switched). So there are only half as many, or 60 permutations.* (the correct terminology is "permutation". "combination" means something else.)
How many different five letter permutations can be formed fron the letters of the word ditto?
The only five letter word that can be made with those letters is 'ditto'.Other words that can be made with the letters in 'ditto' are:dodotIidittotot
How many different 4 letter combinations can you make with 6 different letters?
6P4 = 6!/(6-4)! = 6 * 5 * 4 * 3 = 360 four letter permutations from 6 different letters.6C4 = 6!/[4!∙(6-4)!] = 15 four letter combinationsfrom 6 different letters.
How many different three letter permutations can be formed from the letters in the word clipboard?
There are three that I can see, there's clip, board and lip.
How may different nine-letter permutations can be formed from the nine letters in the word isosceles?
9*8*7 / 2! / 3!
