10 choices (0-9)* 9 choices (the 9 left from choice 1) * 8 choices (the 8 left from choice 2) *3 choices (one of the ones you already used)
10*9*8*3 = 2160 different 4 digit numbers using 3 digits
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Using the digits of 1345678, there are 210 three digit numbers in which no digit is repeated.
You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
6 possible 3 digit combonations
100122 or, if negative numbers are permitted, -998877