There are 195 3-letter permutations.
There are 9 * 8 * 7, or 504, three letter permutations that can be made from the letters in the work CLIPBOARD.
3x2x1=6 permutations.
10! permutations of the word "Arithmetic" may be made.
The word "freezer" has 7 letters, with the letter "e" appearing twice and the letter "r" appearing twice. The number of distinct permutations can be calculated using the formula for permutations of a multiset: ( \frac{n!}{n_1! , n_2! , \ldots , n_k!} ), where ( n ) is the total number of letters and ( n_i ) are the frequencies of the repeated letters. Thus, the number of permutations is ( \frac{7!}{2! \times 2!} = \frac{5040}{4} = 1260 ). Therefore, there are 1,260 distinct permutations of the word "freezer."
There are 195 3-letter permutations.
There are 7893600 permutations.
There are 9 * 8 * 7, or 504, three letter permutations that can be made from the letters in the work CLIPBOARD.
There are 5*4*3 = 60 permutations.
5040
3x2x1=6 permutations.
There are 8! = 40320 permutations.
The number of permutations of the letter ABCDEF is 6 factorial, or 720.
4! 4 * 3 * 2 * 1 = 24
There are 6! = 720 permutations.
If you mean permutations of the letters in the word "obfuscation", the answer is 1,814,400.
The Greek letter pi. pi(abcd) represents permutations of the letters in the set {a,b,c,d}.