3 - hht, hth, thh
I TRIED to use capital letters and got a "take the caps lock off".
I have always used capital letters to indicate heads and tails, but the answer is 3.
480
When tossing 4 coins at once, each coin has 2 possible outcomes: heads (H) or tails (T). Therefore, the total number of possible outcomes can be calculated as (2^4), which equals 16. This means there are 16 different combinations of heads and tails when tossing 4 coins.
3
Heads or tails; each have a probability of 0.5 (assuming a fair coin).
To find the probability of getting exactly two heads when tossing a coin three times, we first determine the total number of possible outcomes, which is (2^3 = 8). The favorable outcomes for getting exactly two heads are: HHT, HTH, and THH, totaling 3 outcomes. Therefore, the probability of getting exactly two heads is ( \frac{3}{8} ).
The outcomes are: heads, tails, tails or tails, heads, tails or tails, tails, heads. You can see that there are 3 possible outcomes with exactly 1 head.
480
When tossing 4 coins at once, each coin has 2 possible outcomes: heads (H) or tails (T). Therefore, the total number of possible outcomes can be calculated as (2^4), which equals 16. This means there are 16 different combinations of heads and tails when tossing 4 coins.
3
Heads or tails; each have a probability of 0.5 (assuming a fair coin).
To find the probability of getting exactly two heads when tossing a coin three times, we first determine the total number of possible outcomes, which is (2^3 = 8). The favorable outcomes for getting exactly two heads are: HHT, HTH, and THH, totaling 3 outcomes. Therefore, the probability of getting exactly two heads is ( \frac{3}{8} ).
There are 210 total possible outcomes from flipping a coin 10 times.There is one possible outcome where there are 0 heads.There are 10 possible outcomes where there is 1 head.So there are 210 - 11 possible outcomes with at least 2 heads.(1013)
There are 24 possible outcomes: January-Heads, January-Tails, February-Heads, February-Tails, March-Heads, and so on.
three heads two head, one tails one heads, two tails three tails
There are 4 possible outcomes, HH, HT, TH, TT. If we assume the odds of tossing heads or tails on any toss is 1/2 (50:50) the odds of tossing heads twice in a row is 1/4 (or 25%).
Each coin can come out either heads (H) or tales (T). Since you're tossing four coins at once, I'm assuming there is no sense of order to be accounted for. In that case, the possible outcomes are the following: HHHH HHHT HHTT HTTT TTTT
To determine the number of leaves on a tree diagram representing all possible combinations of tossing a coin and drawing a card from a standard deck of cards, we first note that there are 2 possible outcomes when tossing a coin (heads or tails) and 52 possible outcomes when drawing a card. Therefore, the total number of combinations is 2 (coin outcomes) multiplied by 52 (card outcomes), resulting in 104 leaves on the tree diagram.