Infinitely many.
Select any number, W, such that 0 < W ≤ 15. Since numbers are infinitely dense, there are infinitely many possible values for W. Let L = 30 - W. Then W ≤ L so each choice of W leads to a unique pair (W, L).
Now, a rectangle with width W cm and length L cm has a perimeter of 2*(L+W) = 2*(30 - W + W) = 2*30 = 60 cm, as required.
Depends what you are drawing on.
There is an infinite number that can have that perimeter
thare is only 1 differint rectangles
15
The perimeter is 60 mm
There would be an infinite number of rectangles possible
Depends what you are drawing on.
An arbitrary large number is the answer for anyrectangle, up to that with a length of 9cm, and 0cm as the width will have a perimeter of 18cm.Similarly, any rectangle up to that with sides 0cm long, and a width of 9cm will have your 18cm perimeter.
There is an infinite number that can have that perimeter
thare is only 1 differint rectangles
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
15
the answer is 12
NONE
13
Infinite amounts.
The perimeter is 60 mm