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How many roots does y equals x2 - 6x plus 9 have?
one
Is x2-6x plus 9 can factor?
x2-6x+9 = (x-3)(x-3) when factorised.
How do you solve x2 - 6x - 13 equals 14?
If: x2-6x-13 = 14 Then: x2-6x-27 = 0 And: (x+3)(x-9) = 0 So: x = -3 or x = 9
What are the solutions in completing the square x2 plus 6x equals 7?
x2 + 6x = 7 ⇒ x2 + 6x + 9 = 7 + 9 ⇒ (x + 3)2 = 16 ⇒ x + 3 = ±4 ⇒ x = -7 or 1
If x2 plus 6x equals 27 what is the value of x?
x2 +6x = 27 x2 + 6x - 27 = 0 x2 + 9x - 3x - 27 = 0 x(x + 9) - 3(x + 9) =0 (x - 3)(x + 9) = 0 So x can equal 3 or -9.
How many roots does y x2 - 6x 9 have?
It has two equal roots which are 3
How many roots does y equals x2 - 6x plus 9 have?
one
What are the roots of x2 plus 6x plus 12 equals 0?
x2 + 6x + 12 = 0 x2 + 6x + 9 = -3 (x + 3)2 = -3 x + 3 = ± √-3 x = -3 ± i√3
What are the roots of the following equation x2 plus 6x plus 2 equals 9?
x^2+6x+2=9 x^2+6x-7=0 (x+7)(x-1)=0 x=-6,1 for your roots
Is x2-6x plus 9 can factor?
x2-6x+9 = (x-3)(x-3) when factorised.
X2 plus 6x plus 9 equals 81?
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
What is the factor of this trinomial x2-6x-27?
x2-6x-27 = (x+3)(x-9) when factored
Which of the following is the vertex of the function yx2-6x 9?
y=x2-6x+9
How do you solve x2 - 6x - 13 equals 14?
If: x2-6x-13 = 14 Then: x2-6x-27 = 0 And: (x+3)(x-9) = 0 So: x = -3 or x = 9
What are the factors of the polynomial below x2 6x-27?
x2 + 6x - 27 = (x + 9)(x - 3)
What are the solutions in completing the square x2 plus 6x equals 7?
x2 + 6x = 7 ⇒ x2 + 6x + 9 = 7 + 9 ⇒ (x + 3)2 = 16 ⇒ x + 3 = ±4 ⇒ x = -7 or 1
If x2 plus 6x equals 27 what is the value of x?
x2 +6x = 27 x2 + 6x - 27 = 0 x2 + 9x - 3x - 27 = 0 x(x + 9) - 3(x + 9) =0 (x - 3)(x + 9) = 0 So x can equal 3 or -9.
