24 two digit number, which sum is greter than their product.
Which are following:
10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 30, 31, 40, 41, 50, 51, 60, 61, 70, 71, 80, 81, 90, 91
You had me until "product." The product of 4 digits can't be prime.
The product of a 4-digit multiplicand and a 1-digit multiplier can have either 4 or 5 digits. If the 4-digit number is multiplied by a multiplier of 1 to 9, the product will typically have 4 digits. However, if the multiplicand is multiplied by 10 (the maximum value for a 1-digit number), the product can reach a maximum of 5 digits. Thus, the product can range from 4 to 5 digits, depending on the specific numbers involved.
The 2-digit number must be 20, because it is the only 2-digit number whose sum of its two even digits, 2 + 0 = 2, is greater than the product of its two even digits, 2 x 0 = 0. Moreover, 20 is a product of the two consecutive integers 4 and 5.
There are 15 of them.
There are three such numbers: 12, 24 and 36.
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
You had me until "product." The product of 4 digits can't be prime.
It can have 4 digits, because the highest possible two digit numbers 99*99=9801.
The product of a 4-digit multiplicand and a 1-digit multiplier can have either 4 or 5 digits. If the 4-digit number is multiplied by a multiplier of 1 to 9, the product will typically have 4 digits. However, if the multiplicand is multiplied by 10 (the maximum value for a 1-digit number), the product can reach a maximum of 5 digits. Thus, the product can range from 4 to 5 digits, depending on the specific numbers involved.
The 2-digit number must be 20, because it is the only 2-digit number whose sum of its two even digits, 2 + 0 = 2, is greater than the product of its two even digits, 2 x 0 = 0. Moreover, 20 is a product of the two consecutive integers 4 and 5.
There are 15 of them.
from 3 digits (10x10) to 4 digits (99X99)
Oh, dude, you want to know the unit's digits of the product of the first 21 prime numbers? Well, let me casually tell you that the unit's digit of a product depends on the unit's digits of the numbers being multiplied. Since the unit's digit of all prime numbers greater than 5 is either 1, 3, 7, or 9, the product of the first 21 prime numbers will end in a unit's digit that is a result of multiplying these digits together. Cool, right?
To find the last but one digit in the product of the first 75 even natural numbers, we need to consider the units digit of each number. Since we are multiplying even numbers, the product will end in 0. Therefore, the last but one digit (tens digit) will depend on the multiplication of the tens digits of the numbers. The tens digit will be determined by the pattern of the tens digits of the even numbers being multiplied.
-21
There are three such numbers: 12, 24 and 36.
4 Give examples to support your answer please.