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How many widths equal one length?
If the length is L units and the width is W units then L/W widths equal one length.
What are the dimension of a rectangle with 60 square units?
The area of a rectangle does not provide enough information. Let L be any number greater than sqrt(60) = approx 7.75 and let B = 60/L. Then a rectangle with length L units and Breadth B units will have an area of L*B = L*(60/L) = 60 square units. Since L can be any number greater than 7.75, there are infiitely many choices for L and so infinitely many possible rectangles.
How many different rectangles can you make with a area of 24?
Infinitely many. Select any number L, greater than sqrt(24) units an let B = 24/L. then the rectangle with sides measuring L and B will have an area of L*B = L*24/L = 24 square units. Also, B ≤ sqrt(24) ≤ L so that value of L gives a different rectangle. And, since there are infinitely many possible values for L, there are infinitely many possible rectangles.
How much is 3.5 L into units?
3.5L into units
What is the length and width of a rectangle with an area of 225 units?
There are infinitely many possible answers based on the information provided. Let L be any number greater than or equal to 15. and let W = 225/L Then W < L and L*W = *225/L = 225 There are infinitely many values for L. For each value of L, there is a corresponding value for W and a rectangle with length L width W will have an area of 225 units, as required.
What is the abbervation for length?
there are many units of length .But ,abbervation for length is reprersented by letter l.
How many widths equal one length?
If the length is L units and the width is W units then L/W widths equal one length.
What are the dimension of a rectangle with 60 square units?
The area of a rectangle does not provide enough information. Let L be any number greater than sqrt(60) = approx 7.75 and let B = 60/L. Then a rectangle with length L units and Breadth B units will have an area of L*B = L*(60/L) = 60 square units. Since L can be any number greater than 7.75, there are infiitely many choices for L and so infinitely many possible rectangles.
How many possible rectangles with an area of 24 square units?
Infinitely many.Let L be any number greater than or equal to sqrt(24) units.and let B = 24/LThen the area of the rectangle with length L units and breadth B units will beL * B = L *24/L = 24 square units.Since there are infinitely many possible values for L, there are infinitely many possible answers to the question.
How many points is the letter L worth in Scrabble?
The letter L is worth 1 point.
How many 16 oz are in a L?
That is approximately 2.23 units of 16 oz.
How do you find the perimeter of a rectangle when given area?
You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.
How many dm3 in a L?
There are 1 dm^3 in 1 L. Both units measure volume and are equivalent.
How many different rectangles can you make with a area of 24?
Infinitely many. Select any number L, greater than sqrt(24) units an let B = 24/L. then the rectangle with sides measuring L and B will have an area of L*B = L*24/L = 24 square units. Also, B ≤ sqrt(24) ≤ L so that value of L gives a different rectangle. And, since there are infinitely many possible values for L, there are infinitely many possible rectangles.
How much is 3.5 L into units?
3.5L into units
What is the length and width of a rectangle with an area of 225 units?
There are infinitely many possible answers based on the information provided. Let L be any number greater than or equal to 15. and let W = 225/L Then W < L and L*W = *225/L = 225 There are infinitely many values for L. For each value of L, there is a corresponding value for W and a rectangle with length L width W will have an area of 225 units, as required.
How many rectangles are possible for 28 square units?
Infinitely many. Select any number between 0 and sqrt(28) and call it W.Then let L = 28/W.A rectangle with length L units and width W units will have an area of LxW = (28/W)*W = 28 square units. And, since W could be any one of infinitely many numbers between 0 and sqrt(28), there are infinitely many possible answers.Infinitely many. Select any number between 0 and sqrt(28) and call it W.Then let L = 28/W.A rectangle with length L units and width W units will have an area of LxW = (28/W)*W = 28 square units. And, since W could be any one of infinitely many numbers between 0 and sqrt(28), there are infinitely many possible answers.Infinitely many. Select any number between 0 and sqrt(28) and call it W.Then let L = 28/W.A rectangle with length L units and width W units will have an area of LxW = (28/W)*W = 28 square units. And, since W could be any one of infinitely many numbers between 0 and sqrt(28), there are infinitely many possible answers.Infinitely many. Select any number between 0 and sqrt(28) and call it W.Then let L = 28/W.A rectangle with length L units and width W units will have an area of LxW = (28/W)*W = 28 square units. And, since W could be any one of infinitely many numbers between 0 and sqrt(28), there are infinitely many possible answers.
