If length and width are doubled than the volume should multiply by 8.
if length and width are doubled then the volume should mulitiply by 8
If only the length is doubled, the volume is also doubled.If only the length is doubled, the volume is also doubled.If only the length is doubled, the volume is also doubled.If only the length is doubled, the volume is also doubled.
The area before would be 13.5 in2. When the length and width are doubled, the new length is 9 inches and the new width is 6 inches, giving the new rectangle an area of 54 in2. Subtract 13.5 from 54, giving you 40.5, which is the difference and the change of the area. Work A=lw A=(4.5 in)(3 in) A=13.5 in2 A=lw A=(9 in)(6 in) A=54 in2
If the length and width of a rectangle is doubled, it means that both dimensions have increased by a factor of 2. As a result, the area of the rectangle will increase by a factor of 4, because the area is calculated by multiplying the length and width together. Additionally, the perimeter of the rectangle will also increase by a factor of 2, since it is calculated by adding the lengths of all four sides.
Assuming no change in the width, yes.
A rectangle has two dimensions - length and width. Only if both dimensions are doubled, then the perimeter will be doubled.
It becomes a bigger rectangle - possibly a square.
Area = length*width new Area = 2 * length * width Area is doubled
300% The volume of the original box is ?. The volume of the box with the length and depth doubled is ?. The amount of change in volume is 60 - 15 = 45. The percent change is the amount of change in volume divided by the original volume:
Perimeter of a rectangle = 2(length + breadth) if one of it's side is doubled then, the resultant perimeter will be 2(2length + breadth) or 2(length + 2 breadth) as the case may be.
You wind up with 6 times the original area.
It would be 4 times greater.To find this algebraically: let L be the length and W the width originallyA = L x WWhen both are doubled, the equation becomesA = (2L) x (2W) = 4LWThe area of the rectangle is quadrupled if both the length and width are doubled.
If length and width are doubled than the volume should multiply by 8.
Its area is now eight times greater than its original size. If area = L x H, then 2(L) x (4)H = 8 (original area)
if length and width are doubled then the volume should mulitiply by 8
the perimeter will double. but the area should doubled to four