When the breadth of a rectangle is doubled, the area of the rectangle also doubles. The area of a rectangle is calculated by multiplying its length by its breadth (Area = Length × Breadth). Therefore, if the original breadth is increased to twice its size, the new area becomes Area = Length × (2 × Breadth), resulting in double the original area.
If length and width are doubled than the volume should multiply by 8.
if length and width are doubled then the volume should mulitiply by 8
If only the length is doubled, the volume is also doubled.If only the length is doubled, the volume is also doubled.If only the length is doubled, the volume is also doubled.If only the length is doubled, the volume is also doubled.
If the base of a triangle is doubled while the other sides remain unchanged, the perimeter of the triangle will increase by the amount equal to the original base length. Specifically, if the original base is ( b ) and the other two sides are ( a ) and ( c ), the new perimeter becomes ( (2b + a + c) ), resulting in an increase of ( b ). Thus, the total perimeter becomes the original perimeter plus the original base length.
When the breadth of a rectangle is doubled, the area of the rectangle also doubles. The area of a rectangle is calculated by multiplying its length by its breadth (Area = Length × Breadth). Therefore, if the original breadth is increased to twice its size, the new area becomes Area = Length × (2 × Breadth), resulting in double the original area.
Assuming no change in the width, yes.
A rectangle has two dimensions - length and width. Only if both dimensions are doubled, then the perimeter will be doubled.
It becomes a bigger rectangle - possibly a square.
Area = length*width new Area = 2 * length * width Area is doubled
300% The volume of the original box is ?. The volume of the box with the length and depth doubled is ?. The amount of change in volume is 60 - 15 = 45. The percent change is the amount of change in volume divided by the original volume:
Perimeter of a rectangle = 2(length + breadth) if one of it's side is doubled then, the resultant perimeter will be 2(2length + breadth) or 2(length + 2 breadth) as the case may be.
You wind up with 6 times the original area.
It would be 4 times greater.To find this algebraically: let L be the length and W the width originallyA = L x WWhen both are doubled, the equation becomesA = (2L) x (2W) = 4LWThe area of the rectangle is quadrupled if both the length and width are doubled.
If length and width are doubled than the volume should multiply by 8.
Its area is now eight times greater than its original size. If area = L x H, then 2(L) x (4)H = 8 (original area)
if length and width are doubled then the volume should mulitiply by 8