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y = 4x² + 16x ; Take the derivative: y' = 8x + 16. Set equal to zero, and x = -2.
Substitute into the original: y = 4(-2)² + 16*(-2) = -16, so the vertex is (-2,16).
Or, factor to y = 4x(x + 4).
The zeros of this are x = 0 and x = -4.
Since a parabola is symmetric, the vertex is halfway between these, or x = -2, then substitute as above and get (-2,16).
What else can I help you with?
Find the vertex of y equals x2 plus 10x plus 22?
-2-5
Vertex for y equals x2 plus 2x plus 1?
The vertex is at (-1,0).
What is the vertex of the parabola y equals x2 plus 8x plus 5?
The vertex has a minimum value of (-4, -11)
What is the vertex of y equals x-3 plus 2?
The equation is linear and so has no vertex.
What is the vertex of the function y equals x squared plus 4?
The vertex is at the point (0, 4).
Find the vertex of y equals x2 plus 10x plus 22?
-2-5
Vertex for y equals x2 plus 2x plus 1?
The vertex is at (-1,0).
What is the vertex of the parabola y equals x2 plus 8x plus 5?
The vertex has a minimum value of (-4, -11)
What is the vertex of y equals x-3 plus 2?
The equation is linear and so has no vertex.
What is the vertex of the function y equals x squared plus 4?
The vertex is at the point (0, 4).
What is the vertex of y equals x plus 1?
y = x +1 is the equation of a straight line and so has no vertex.
What is the vertex of y equals x2-6x plus 6?
(3, -21)
What is the vertex form of y equals x2 plus 4x - 7?
The vertex of the positive parabola turns at point (-2, -11)
How do you write y equals x minus 4 x plus 2 in vertex form and find the vertex?
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
How do you find the vertex of 2x2 plus 4 plus 1?
2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)
What is the vertex of the parabola y equals 2x squared plus 12x 13?
(-3, -5)
What is the vertex of the function y equals x2 plus 6x-5?
x = -3y = -14
