To determine which number is divisible by 3, 6, and 9, we need to check if the sum of the digits of each number is divisible by 3. For 369: 3+6+9 = 18, which is divisible by 3, 6, and 9. Therefore, 369 is divisible by 3, 6, and 9. For 246: 2+4+6 = 12, which is divisible by 3 but not by 6 or 9. Therefore, 246 is divisible by 3 but not by 6 or 9. For 468: 4+6+8 = 18, which is divisible by 3, 6, and 9. Therefore, 468 is divisible by 3, 6, and 9. For 429: 4+2+9 = 15, which is divisible by 3 but not by 6 or 9. Therefore, 429 is divisible by 3 but not by 6 or 9. Therefore, the numbers 369 and 468 are divisible by 3, 6, and 9.
432, 468
yes the answear is 156 :)
234, 468, 702 and so on.
936 is one of an infinite number of numbers
468 is divisible by all of its factors, 1, 2, 3, 4, 6, 9, 12, 13, 18, 26, 36, 39, 52, 78, 117, 156, 234, and 468.
432, 468
Yes, 468 divided by 4 is 117.
2 and 3 yes, 5 no.
To determine which number is divisible by 3, 6, and 9, we need to check if the sum of the digits of each number is divisible by 3. For 369: 3+6+9 = 18, which is divisible by 3, 6, and 9. Therefore, 369 is divisible by 3, 6, and 9. For 246: 2+4+6 = 12, which is divisible by 3 but not by 6 or 9. Therefore, 246 is divisible by 3 but not by 6 or 9. For 468: 4+6+8 = 18, which is divisible by 3, 6, and 9. Therefore, 468 is divisible by 3, 6, and 9. For 429: 4+2+9 = 15, which is divisible by 3 but not by 6 or 9. Therefore, 429 is divisible by 3 but not by 6 or 9. Therefore, the numbers 369 and 468 are divisible by 3, 6, and 9.
The infinite set of numbers characterised by 468*k where k is an integer.
yes the answear is 156 :)
468
234, 468, 702 and so on.
936 is one of an infinite number of numbers
The number is 468.
468 x 2 = 936