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What are the rules when squaring a log squaring the whole log?
this is the question (log (base2) (x))^2- 12(log (base 2) (x)) + 32 = 0, I don't get this bit (log (base2) (x))^2, note the whole log is squared
Log 2 plus log 4 equals log 2x?
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
Which power of 2 equal 1024?
Take logs to base '10' Hence log(10)1024 = log(10)2^(n) log(10)1024 = nlog(10)2 n = log(10)1024 / log(10)2 n = 3.0103 / 0.30103 Divide n = 10 Hence 2^(10) = 1024
How do you solve log base 2 of x - 3 log base 2 of 5 equals 2 log base 2 of 10?
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
How do you solve log x plus 2 equals log 9?
log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09
How do you solve log x - 2?
You cannot solve log x- 2 unless (i) log x - 2 is equal to some number or (ii) x is equal to some number.
What are the rules when squaring a log squaring the whole log?
this is the question (log (base2) (x))^2- 12(log (base 2) (x)) + 32 = 0, I don't get this bit (log (base2) (x))^2, note the whole log is squared
What is log 2?
Log 2 is the exponent to which 10 must be raised to equal 2, which is approximately 0.301.
How many times do you have to times 2 for it to equal 16384?
You will need 14 two's multiplied together to equal 16384. the answer to this can be found by log2(16384) = 14. Since most calculators don't have log base 2, you can do this: log(16384)/log(2) = 14. You can use the 'base 10' log or natural log [ln(16384)/ln(2) = 14]
Log x plus log 2 equals log 2?
log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1
Log 2 plus log 4 equals log 2x?
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
If 3 log x - 2 log y?
1
Log base 3 of 81 plus log base 3 of 81?
Log base 3 of 81 is equal to 4, because 3 ^ 4 = 81. Therefore, two times log base 3 of 81 is equal to 2 x 4 = 8.
Is log 5 equivalent to log 5-log 20?
No. log 20 is a positive number , so it you subtract it from log 5 you get less than log 5. However, log10 5 = 1 - log102 = 2- log1020 . or log 5 - log 20 = log 5 - log 4*5 = log 5 - (log 5 + log 4) = log 5 - log 5 - log 4 = - log 4 But we do not need to do all of these computations, because log 5 is different from log 5 - log 20 by the law of the equality that says two equals remain equal if and only if we subtract (in our case) the same thing from them.
What are the release dates for Adam-12 - 1968 Log 43 Hostage 2-12?
Adam-12 - 1968 Log 43 Hostage 2-12 was released on: USA: 3 January 1970
What are the release dates for Navy Log - 1955 Buzz Boy 2-12?
Navy Log - 1955 Buzz Boy 2-12 was released on: USA: 2 January 1957
How do you solve 3 to the power of negative 2x plus 2 equals 81?
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
