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Log 2 plus log 4 equals log 2x?
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
Which power of 2 equal 1024?
Take logs to base '10' Hence log(10)1024 = log(10)2^(n) log(10)1024 = nlog(10)2 n = log(10)1024 / log(10)2 n = 3.0103 / 0.30103 Divide n = 10 Hence 2^(10) = 1024
How do you solve log base 2 of x - 3 log base 2 of 5 equals 2 log base 2 of 10?
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
What is log 0.5 to the base 2?
The logarithm of 0.5 to the base 2, written as log₂(0.5), is equal to -1. This is because 2 raised to the power of -1 equals 0.5 (i.e., 2^(-1) = 1/2 = 0.5). Thus, log₂(0.5) = -1.
What are the rules when squaring a log squaring the whole log?
Oh, dude, squaring a log is like squaring anything else - you just multiply it by itself. So, if you square the log of a number, you're just raising that number to the power of the log base twice. It's not rocket science, just some basic algebraic manipulation. Hope that clears things up for you!
