Let's see what combinations can be formed.
HH, HH, Hh, Hh.
So, yes their offspring can contain the recessive allele.
(THe offspring can be a carrier of the recessive allele.)
However, since it is impossible for the offspring to be homozygous recessive,
the recessive trait/gene will not show in the offspring's phenotype.
Hope that helps!
In a cross between a homozygous recessive parent (AA) and a heterozygous parent (Aa), the possible genotypes of the offspring are 50% homozygous recessive (AA) and 50% heterozygous (Aa). Therefore, the probability that an offspring will be homozygous recessive is 50%.
In a dihybrid cross between two heterozygous parents (AaBb x AaBb), the probability of producing homozygous recessive offspring for both traits (aabb) is 1/16. This is derived from the Punnett square, where the combinations of alleles reveal that out of 16 possible offspring, only one combination results in homozygous recessive for both traits. Thus, the fraction of homozygous recessive offspring is 1/16.
The probability of a homozygous recessive offspring depends on the genotypes of the parents. If we consider a simple Mendelian trait with two alleles (dominant "A" and recessive "a"), a homozygous recessive offspring (aa) will occur if both parents contribute a recessive allele. For instance, if both parents are heterozygous (Aa), the probability of producing a homozygous recessive offspring is 25%, as determined by a Punnett square. If one parent is homozygous dominant (AA) and the other is homozygous recessive (aa), the probability of a homozygous recessive offspring is 0%.
The homozygous dominant individual can only pass on the dominant allele and the homozygous recessive individual can only pass on the recessive allele, therefore all offspring will be heterozygous and have the dominant phenotype.
The probability that the offspring of a homozygous dominant parent (AA) and a heterozygous parent (Aa) will show a recessive phenotype is 0%. Since the homozygous dominant parent contributes only dominant alleles (A), all offspring will inherit at least one dominant allele (A) from the homozygous parent, resulting in either a homozygous dominant (AA) or a heterozygous (Aa) genotype, both of which express the dominant phenotype.
A test cross between a homozygous recessive and a heterozygous individual will yield 50% of offspring as homozygous recessive. This is because all the offspring will inherit one recessive allele from the homozygous recessive parent.
In a cross between a homozygous recessive parent (AA) and a heterozygous parent (Aa), the possible genotypes of the offspring are 50% homozygous recessive (AA) and 50% heterozygous (Aa). Therefore, the probability that an offspring will be homozygous recessive is 50%.
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.
1/2 or 50%. The homozygous recessive gentoype contains two recessive alleles for the gene for a trait. So the homozygous recessive individual can pass on only recessive alleles to an offspring. The heterozygous individual has one dominant and one recessive allele for the gene for a trait. So the heterozygous individual can pass on either a dominant or a recessive allele to an offspring. So if an offspring inherits a recessive allele from the heterozygous parent, along with the recessive allele from the homozygous recessive parent, it will have the homozygous recessive genotype and phenotype.
There are 3 probabilities: dominant homozygous, recessive homozygous, or heterozygous.
To determine if a plant is homozygous or heterozygous, you would need to test cross it with a homozygous recessive plant. If the offspring show the recessive trait, the original plant is heterozygous; if all offspring show the dominant trait, the original plant is homozygous.
25%
The offspring will all inherit one copy of the dominant allele (from the heterozygous parent) and one copy of the recessive allele (from the homozygous recessive parent). This results in all offspring being heterozygous for the trait.
To determine if a particular plant is homozygous or heterozygous, you would need to perform a test cross with a homozygous recessive individual. If the offspring display the recessive trait, the original plant would likely be heterozygous. If all offspring exhibit the dominant trait, the original plant would likely be homozygous dominant.
In a dihybrid cross between two heterozygous parents (AaBb x AaBb), the probability of producing homozygous recessive offspring for both traits (aabb) is 1/16. This is derived from the Punnett square, where the combinations of alleles reveal that out of 16 possible offspring, only one combination results in homozygous recessive for both traits. Thus, the fraction of homozygous recessive offspring is 1/16.
There is a 50% chance of a homozygous dominant and a 50% chance of a heterozygous.