Let's see what combinations can be formed.
HH, HH, Hh, Hh.
So, yes their offspring can contain the recessive allele.
(THe offspring can be a carrier of the recessive allele.)
However, since it is impossible for the offspring to be homozygous recessive,
the recessive trait/gene will not show in the offspring's phenotype.
Hope that helps!
The homozygous dominant individual can only pass on the dominant allele and the homozygous recessive individual can only pass on the recessive allele, therefore all offspring will be heterozygous and have the dominant phenotype.
It depends. If it's a heterozygous cross, (Tt x Tt), there's a 25% chance. If it's a homozygous dominant cross (TT x TT), the chance is 0%. Neither parent has the alleles for a recessive trait, so none of their offspring can have the recessive trait. If it's a homozygous recessive cross (tt x tt), there's a 100% chance. The only alleles the parents can pass on are recessive.
Straight thumbs, hitch hiker's thumb is recessive...so the F1 generation in this example would be heterozygous and have the dominant (straight thumbed) phenotype.
well, it depends on the genes of the parents
100 percent.
A test cross between a homozygous recessive and a heterozygous individual will yield 50% of offspring as homozygous recessive. This is because all the offspring will inherit one recessive allele from the homozygous recessive parent.
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.
1/2 or 50%. The homozygous recessive gentoype contains two recessive alleles for the gene for a trait. So the homozygous recessive individual can pass on only recessive alleles to an offspring. The heterozygous individual has one dominant and one recessive allele for the gene for a trait. So the heterozygous individual can pass on either a dominant or a recessive allele to an offspring. So if an offspring inherits a recessive allele from the heterozygous parent, along with the recessive allele from the homozygous recessive parent, it will have the homozygous recessive genotype and phenotype.
The probability of offspring for two heterozygous dogs (Aa x Aa) is 25% homozygous dominant (AA), 50% heterozygous (Aa), and 25% homozygous recessive (aa) based on Mendelian genetics principles.
To determine if a plant is homozygous or heterozygous, you would need to test cross it with a homozygous recessive plant. If the offspring show the recessive trait, the original plant is heterozygous; if all offspring show the dominant trait, the original plant is homozygous.
25%
The offspring will all inherit one copy of the dominant allele (from the heterozygous parent) and one copy of the recessive allele (from the homozygous recessive parent). This results in all offspring being heterozygous for the trait.
To determine if a particular plant is homozygous or heterozygous, you would need to perform a test cross with a homozygous recessive individual. If the offspring display the recessive trait, the original plant would likely be heterozygous. If all offspring exhibit the dominant trait, the original plant would likely be homozygous dominant.
There is a 50% chance of a homozygous dominant and a 50% chance of a heterozygous.
The homozygous dominant individual can only pass on the dominant allele and the homozygous recessive individual can only pass on the recessive allele, therefore all offspring will be heterozygous and have the dominant phenotype.
Out of the 240 offspring, approximately 60 would be homozygous (25% of 240). This is because when two heterozygous plants are crossed (Aa x Aa), the Punnett square shows that 25% of the offspring will be homozygous dominant (AA), 50% will be heterozygous (Aa), and 25% will be homozygous recessive (aa).