Chat with our AI personalities
145 1! = 1 4! = 24 5! = 120
If, as is normal, ab represents a times b, etc then ab + ab + cc = 2ab + c2 which is generally not the same as abc.
31,875,000
abc = 183.if abc + abc = cdd and d = 6, then:abc + abc + c66So, looking at the units:c + c = 6 possibly plus carry⇒ c = 3 (no carry) or c = 8 (carry)Looking at the tens:b + b + possible_carry_from_units = 6⇒ 2b + possible_carry = 62b is even, 6 is even, so the possible_carry must be even.The possible_carry is either 0 or 1; 1 is odd, so it must be 0, so c must be 3 (c = 3).This leave 2b = 6 possibly plus carry⇒ b = 3 (no carry) or b = 8 (carry)Looking at the hundreds:a + a + possible_carry_from_tens = c = 3 (as just found)⇒ 2a + possible_carry = 32b is even, 3 is odd, so the possible_carry must be odd.The possible_carry is either 0 or 1; 1 is odd, so it must be 1, so b must be 8 (b = 8).This leaves 2a + 1 = 3⇒ 2a = 2⇒ a = 1Making the number abc = 183.
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc