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Acceleration of gravity is 9.8 m/s.

If you hold your hand steady and drop the rock, its downward speed

after 3 seconds is (9.8 x 3) = 29.4 m/s.

If you throw it down and it leaves your hand with a speed of 'S', then

its downward speed after 3 seconds is (S+29.4) m/s.

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Suppose a rock is dropped off a cliff with an initial speed of 0ms. what is the rocks speed after 5 second in ms if it encounters no air resistance?

The speed of the rock after 5 seconds, neglecting air resistance, can be determined using the equation: speed = initial velocity + acceleration * time. Since the initial speed is 0 m/s, and assuming the acceleration due to gravity is 9.81 m/s², the speed of the rock after 5 seconds would be 49.05 m/s.


Suppose a rock is dropped off a cliff with an initial speed of 0 ms. What is the rocks speed after 5 seconds in ms if it encounters no air resistance?

The rock would have a speed of 49 m/s after 5 seconds of free fall due to gravity (assuming g = 9.81 m/s^2). This is because its speed increases by 9.81 m/s every second during free fall.


When an object falls through the air and encounters air resistance it's overall speed will be what?

When an object falls through the air and encounters air resistance, its overall speed will decrease compared to if it were falling in a vacuum. Air resistance creates a force in the opposite direction of motion which slows down the object.


When an object fall through the air and encounters air resistance its overall speed will be than if it had not encountered air resistance?

Slower. Air resistance acts in the opposite direction to the motion of the object, reducing its speed as it falls.


Suppose a rock is dropped off a cliff with an initial speed of 0 ms. What is the rock's speed after 5 seconds in ms if it encounters no air resistance?

The rock's speed after 5 seconds would be approximately 49 m/s. This is calculated using the formula v = g * t, where v is the final speed, g is the acceleration due to gravity (9.8 m/s^2), and t is the time elapsed (5 seconds).

Related Questions

Suppose a rock is dropped off a cliff with an initial speed of 0 m per sec What is the rocks speed after 5 seconds in m per sec if it encounters no air resistance?

9.8m/s(5)= 49


Suppose a rock is dropped off a cliff with an initial speed of 0 What is the rock's speed after 5 seconds in if it encounters no air resistance?

49


Suppose a rock is dropped off a cliff with an initial speed of 0 ms What is the rock's speed after 3 seconds in ms if it encounters no air resistance?

29.4


Suppose a rock is dropped off a cliff with an initial speed of 0 ms What is the rock's speed after 5 seconds in ms if it encounters no air resistance?

49


Suppose a rock is dropped off a cliff with an initial speed of 0 ms What is the rocks speed after 3 seconds in ms if it encounters no air resistance?

The acceleration of gravity is 9.8 m/s2Speed after 3 sec = (9.8 x 3) = 29.4 m/s


Suppose a rock is dropped off a cliff with an initial speed of 0ms. what is the rocks speed after 5 second in ms if it encounters no air resistance?

The speed of the rock after 5 seconds, neglecting air resistance, can be determined using the equation: speed = initial velocity + acceleration * time. Since the initial speed is 0 m/s, and assuming the acceleration due to gravity is 9.81 m/s², the speed of the rock after 5 seconds would be 49.05 m/s.


If a rock is dropped off a cliff with an initial speed of 0 meters per second what is the rocks speed after 5 seconds in meters per second if it encounters no air resistance?

If a rock is dropped from a cliff with an initial speed of 0 meters per second and encounters no air resistance, its speed after 5 seconds can be calculated using the formula for free fall: ( v = g \cdot t ), where ( g ) is the acceleration due to gravity (approximately ( 9.81 , \text{m/s}^2 )) and ( t ) is the time in seconds. After 5 seconds, the speed of the rock would be ( v = 9.81 , \text{m/s}^2 \cdot 5 , \text{s} = 49.05 , \text{m/s} ). Thus, the rock's speed after 5 seconds would be approximately 49.05 meters per second.


Suppose a rock is dropped off a cliff with an initial speed of 0 ms. What is the rocks speed after 5 seconds in ms if it encounters no air resistance?

The rock would have a speed of 49 m/s after 5 seconds of free fall due to gravity (assuming g = 9.81 m/s^2). This is because its speed increases by 9.81 m/s every second during free fall.


Suppose a rock is dropped off a cliff with an initial speed of 0 miles per second What is the rock's speed after 5 seconds in miles per second if it encounters no air resistance?

,033


If a Rock is dropped off a cliff with an initial speed of 0 ms What is the rock's speed after 3 seconds in ms if it encounters no air resistance?

speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s


When an object falls through the air and encounters air resistance it's overall speed will be what?

When an object falls through the air and encounters air resistance, its overall speed will decrease compared to if it were falling in a vacuum. Air resistance creates a force in the opposite direction of motion which slows down the object.


When an object fall through the air and encounters air resistance its overall speed will be than if it had not encountered air resistance?

Slower. Air resistance acts in the opposite direction to the motion of the object, reducing its speed as it falls.