Wiki User
ā 14y agoAcceleration of gravity is 9.8 m/s.
If you hold your hand steady and drop the rock, its downward speed
after 3 seconds is (9.8 x 3) = 29.4 m/s.
If you throw it down and it leaves your hand with a speed of 'S', then
its downward speed after 3 seconds is (S+29.4) m/s.
Wiki User
ā 14y agoThe rock's speed after 3 seconds, with no air resistance, can be calculated using the equation: speed = initial velocity + acceleration Ć time. If the rock is in free fall near the surface of the Earth, the acceleration due to gravity is approximately 9.81 m/s^2. If the rock was dropped from rest, its initial velocity would be 0 m/s. Plugging in the values, the rock's speed after 3 seconds would be 29.43 m/s.
The speed of the rock after 5 seconds, neglecting air resistance, can be determined using the equation: speed = initial velocity + acceleration * time. Since the initial speed is 0 m/s, and assuming the acceleration due to gravity is 9.81 m/sĀ², the speed of the rock after 5 seconds would be 49.05 m/s.
The rock would have a speed of 49 m/s after 5 seconds of free fall due to gravity (assuming g = 9.81 m/s^2). This is because its speed increases by 9.81 m/s every second during free fall.
When an object falls through the air and encounters air resistance, its overall speed will decrease compared to if it were falling in a vacuum. Air resistance creates a force in the opposite direction of motion which slows down the object.
Slower. Air resistance acts in the opposite direction to the motion of the object, reducing its speed as it falls.
The rock's speed after 5 seconds would be approximately 49 m/s. This is calculated using the formula v = g * t, where v is the final speed, g is the acceleration due to gravity (9.8 m/s^2), and t is the time elapsed (5 seconds).
9.8m/s(5)= 49
49
29.4
49
The acceleration of gravity is 9.8 m/s2Speed after 3 sec = (9.8 x 3) = 29.4 m/s
The speed of the rock after 5 seconds, neglecting air resistance, can be determined using the equation: speed = initial velocity + acceleration * time. Since the initial speed is 0 m/s, and assuming the acceleration due to gravity is 9.81 m/sĀ², the speed of the rock after 5 seconds would be 49.05 m/s.
The rock would have a speed of 49 m/s after 5 seconds of free fall due to gravity (assuming g = 9.81 m/s^2). This is because its speed increases by 9.81 m/s every second during free fall.
,033
speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s
When an object falls through the air and encounters air resistance, its overall speed will decrease compared to if it were falling in a vacuum. Air resistance creates a force in the opposite direction of motion which slows down the object.
Slower. Air resistance acts in the opposite direction to the motion of the object, reducing its speed as it falls.
The acceleration of gravity is 32.1 ft/sec2 .After 3 seconds, the rock's downward speed is (3 x 32.1) = 96.3 ft/sec.(96.3 ft/sec) x (1 mi / 5,280 ft) = (96.3 / 5,280) (ft - mi / sec - ft) = 0.0182 mile/sec (rounded)