Acceleration of gravity is 9.8 m/s.
If you hold your hand steady and drop the rock, its downward speed
after 3 seconds is (9.8 x 3) = 29.4 m/s.
If you throw it down and it leaves your hand with a speed of 'S', then
its downward speed after 3 seconds is (S+29.4) m/s.
The speed of the rock after 5 seconds, neglecting air resistance, can be determined using the equation: speed = initial velocity + acceleration * time. Since the initial speed is 0 m/s, and assuming the acceleration due to gravity is 9.81 m/s², the speed of the rock after 5 seconds would be 49.05 m/s.
The rock would have a speed of 49 m/s after 5 seconds of free fall due to gravity (assuming g = 9.81 m/s^2). This is because its speed increases by 9.81 m/s every second during free fall.
When an object falls through the air and encounters air resistance, its overall speed will decrease compared to if it were falling in a vacuum. Air resistance creates a force in the opposite direction of motion which slows down the object.
Slower. Air resistance acts in the opposite direction to the motion of the object, reducing its speed as it falls.
The rock's speed after 5 seconds would be approximately 49 m/s. This is calculated using the formula v = g * t, where v is the final speed, g is the acceleration due to gravity (9.8 m/s^2), and t is the time elapsed (5 seconds).
9.8m/s(5)= 49
49
29.4
49
The acceleration of gravity is 9.8 m/s2Speed after 3 sec = (9.8 x 3) = 29.4 m/s
The speed of the rock after 5 seconds, neglecting air resistance, can be determined using the equation: speed = initial velocity + acceleration * time. Since the initial speed is 0 m/s, and assuming the acceleration due to gravity is 9.81 m/s², the speed of the rock after 5 seconds would be 49.05 m/s.
If a rock is dropped from a cliff with an initial speed of 0 meters per second and encounters no air resistance, its speed after 5 seconds can be calculated using the formula for free fall: ( v = g \cdot t ), where ( g ) is the acceleration due to gravity (approximately ( 9.81 , \text{m/s}^2 )) and ( t ) is the time in seconds. After 5 seconds, the speed of the rock would be ( v = 9.81 , \text{m/s}^2 \cdot 5 , \text{s} = 49.05 , \text{m/s} ). Thus, the rock's speed after 5 seconds would be approximately 49.05 meters per second.
The rock would have a speed of 49 m/s after 5 seconds of free fall due to gravity (assuming g = 9.81 m/s^2). This is because its speed increases by 9.81 m/s every second during free fall.
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speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s
When an object falls through the air and encounters air resistance, its overall speed will decrease compared to if it were falling in a vacuum. Air resistance creates a force in the opposite direction of motion which slows down the object.
Slower. Air resistance acts in the opposite direction to the motion of the object, reducing its speed as it falls.