v = vo + gt = 2(m/s) + 9.8(m/s2) x 5s = 51(m/s)
If a skier is in a jump, then a skier and skydiver is pretty much the same thing. In general though, a skydiver has only air resistance, the skier has air resistance and friction with the ski-snow, so the skydiver has an edge on speed.
The same as that of the aircraft that he /she is in. If flying level, it would be zero.
I presume you mean 1 second after jumping from the plane. Since skydiver's fall, their velocity is generally in a downward direction, so the upward velocity is negative. The formula v = gt, where g is the acceleration due to gravity which is about 32.2 feet per second per second, tells us that after 1 second it would be about -32.2 feet per second.
The general formula for acceleration is [(final velocity) - (initial velocity)]/(time required for the change). In this instance, (5 - 65)/0.75 = -80 meters per second per second.
There are 3 formula 1. Final velocity = starting velocity + (acceleration)(time) 2. Final velocity^2 = starting velocity^2 + 2(acceleration)(distance) 3. Distance = (starting velocity)(time) + 1/2(acceleration)(time^2) Use whichever you can use.
If a skier is in a jump, then a skier and skydiver is pretty much the same thing. In general though, a skydiver has only air resistance, the skier has air resistance and friction with the ski-snow, so the skydiver has an edge on speed.
The shape of the displacement versus time graph for a skydiver would be a curve that starts at zero displacement when the skydiver jumps out of the plane, increases as the skydiver falls accelerating due to gravity, and eventually levels off as the skydiver reaches terminal velocity. The curve will then be a straight line at a constant displacement representing the terminal velocity until the skydiver opens the parachute, at which point the displacement will decrease as the skydiver slows down and lands.
When a skydiver jumps out of a hovering helicopter with forward velocity, the skydiver's initial velocity will be a combination of the helicopter's forward velocity and the vertical velocity due to gravity. As the skydiver falls, their acceleration is primarily due to gravity acting downward, with air resistance also playing a role. The acceleration experienced by the skydiver will be constant at approximately 9.8 m/s^2 downward, ignoring air resistance.
Friction (from air resistance) stops them from falling faster and faster continually - instead they reach a maximum velocity and stay at that speed until they pull their parachute. Friction prevents them from plummeting to their death.
As a skydiver falls, air resistance causes friction against her body, gradually slowing her down. This friction increases as her speed decreases, ultimately leading to a terminal velocity where the forces of gravity and air resistance balance, resulting in a constant falling speed. This friction also helps stabilize the skydiver's position during free fall.
At the moment the skydiver exits the helicopter, their downward velocity is initially zero. As they fall due to gravity, their velocity will increase over time.
The same as that of the aircraft that he /she is in. If flying level, it would be zero.
500 N is pressumably the weight, due to gravity. "Terminal velocity" means that the forces are in balance; the total force acting on the skydiver are zero. This is only possible if there is a 500 N force due to friction, to counteract the weight.
The air resistance on the skydiver at terminal velocity is 500 N. At terminal velocity, the air resistance on the skydiver is equal in magnitude to the gravitational force pulling them downward. This balance of forces results in a constant velocity.
The skydiver's downward velocity just before starting to fall would be zero, as they would be momentarily suspended in the air before gravity starts to accelerate them downwards.
A skydiver typically achieves terminal velocity, the maximum velocity at which they fall through the air, within 10-12 seconds of jumping out of the plane. This usually occurs at around 120 mph (193 km/h) for a skydiver in a belly-to-earth position.
Acceleration due to gravity is 9.8m/s/s, which is the same as 9.8m/s2. An acceleration of 9.8m/s/s means that with each passing second, the velocity of the skydiver increases by 9.8m/s. Therefore, after two seconds. a skydiver's velocity would be 19.6m/s. The acceleration will continue at 9.8m/s/s until the skydiver reaches terminal velocity, at which point the weight of the skydiver and the air resistance will be balanced, so the net force acting on the skydiver will be zero, at which point there will be no further acceleration.