south
Indeed it is.
The cyclist ends up 1 mile east of the starting point (unless the cycling takes place near the north or south pole!). So the displacement is 1 mile in an easterly direction.
To calculate displacement, we determine the net change in position from the starting point. Starting at the origin, you walk 100 m north, then 20 m east, 30 m south, 50 m west, and finally 70 m south. The net movement in the north-south direction is 100 m north - 30 m south - 70 m south = 0 m, and in the east-west direction, it’s 20 m east - 50 m west = -30 m (or 30 m west). Therefore, the displacement is 30 m west.
20m
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
south
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
2 km south
Yes, a position-time graph can tell you the direction of the displacement of an object. If the slope of the graph is positive, the object is moving in the positive direction. If the slope is negative, the object is moving in the negative direction.
The total displacement is 2km north, as the southward and northward displacements cancel each other out.
Indeed it is.
The distance traveled is the sum of the magnitudes of the two displacements: 15.0 m north + 11.0 m south = 4.0 m north. The magnitude of the displacement is the absolute difference between the initial and final positions: |15.0 m - 11.0 m| = 4.0 m.
The total displacement is 30 meters South. Displacement is the difference between the initial and final positions of an object, irrespective of the path taken. In this case, the person returns partially to the initial position after moving North by 50 meters.
This is incorrect. A northerly wind comes from the north and moves toward the south.