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If an object moves 40 m north 40 m west 40 m south and 40 m east what's the total displacement?
The total displacement of the object is zero meters. Although the object moves 40 m in each cardinal direction, it ultimately returns to its starting point. Displacement is a vector quantity that considers only the initial and final positions, and since both are the same, the displacement is zero.
What else can I help you with?
If a Displacement vectors of 4 km south 2 km north 5 km north combine to a total displacement of?
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
If the displacement is negative 2 north and represents a positive displacement What is the direction?
south
A -2 displacement towards the north represents a positive displacement towards the south?
Indeed it is.
What is the total displacement of a child who walks 4 m south 2 m north 5 m south 5 m north?
To find the total displacement, we calculate the net movement in the north-south direction. The child walks 4 m south and then 5 m south, totaling 9 m south. They then walk 2 m north and 5 m north, totaling 7 m north. The net displacement is 9 m south - 7 m north = 2 m south.
What is the correct displacement for the following 4km south 2km north5km south5km north?
To find the correct displacement, we need to consider the net movement in the north-south direction. Starting from the origin, you move 4 km south, then 2 km north, resulting in a net movement of 2 km south. Next, moving 5 km south brings the total to 7 km south, and finally moving 5 km north results in a net position of 2 km south. Thus, the correct displacement is 2 km south.
If a Displacement vectors of 4 km south 2 km north 5 km north combine to a total displacement of?
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
What is the correct displacement for the following vectors 4 km south km north 5 km south and 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the correct displacement for the following vectors 4 km south 2 km north 2 km south and 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
If the displacement is negative 2 north and represents a positive displacement What is the direction?
south
What is the correct displacement for the following vectors 4 km south 2 km north 5 km south 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the correct displacement for the following vectors 4 km south 2 km north 5 km south .5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What are displacement vectors of 2 km south and 6 km north and 5 km south and 6 km north combine to a total displacement of?
2 km south
Can a position time graph tell in which directionthe displacement of an object is?
Yes, a position-time graph can tell you the direction of the displacement of an object. If the slope of the graph is positive, the object is moving in the positive direction. If the slope is negative, the object is moving in the negative direction.
What is the correct displacement for the following vectors 4km south 2km north 5km south and 5km north?
The total displacement is 2km north, as the southward and northward displacements cancel each other out.
A -2 displacement towards the north represents a positive displacement towards the south?
Indeed it is.
An object moves 15.0 m north and then 11.0 m south Find both the distance traveled and the magnitude of the displacement vector?
The total distance traveled (corresponding to the amount of gas the car would burn on such a trip) is 26 meters.The magnitude of the displacement vector = (Dfinal - Dinitial) = 4 meters north.
What is the total displacement of a person that travels 80 meters due South than travels another 50 meters due north?
The total displacement is 30 meters South. Displacement is the difference between the initial and final positions of an object, irrespective of the path taken. In this case, the person returns partially to the initial position after moving North by 50 meters.
