The idea is to replace "x" by its value, to replace "y" by its value, and then to do the calculations.
To simplify (\log(xy)), you can use the logarithmic property that states (\log(xy) = \log(x) + \log(y)). Given (x = 12) and (y = 20), you can calculate (\log(12) + \log(20)). If you need a numerical value, you can evaluate it using a calculator, resulting in approximately (1.0792 + 1.3010 = 2.3802) (using base 10 logarithm).
103
x+xy=8 xy=-x+8 y=-1+8/x
That is irrelevant, there is not possible way y=xy, and there is no possible way xy=x.
So far you know that: x=-8 xy=1 so xy means x times y. If you split xy. y=1/x or y=1/-8 1/-8= -0.125 You can find out that this is correct with the formula xy=1 because -0.125 x -8 is 1.
xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y
To simplify (\log(xy)), you can use the logarithmic property that states (\log(xy) = \log(x) + \log(y)). Given (x = 12) and (y = 20), you can calculate (\log(12) + \log(20)). If you need a numerical value, you can evaluate it using a calculator, resulting in approximately (1.0792 + 1.3010 = 2.3802) (using base 10 logarithm).
The GCF is xy
Xy/y = x
103
-17
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
(x-y) + (xy - 1) = (x - 1)(y + 1)
*Hint*=xy=x mutiplied by y.
x+xy=8 xy=-x+8 y=-1+8/x
xy = x ÷x y = 1
In mathematics, XY square typically refers to the square of the product of two variables, X and Y. This can be represented as (XY)^2 or X^2 * Y^2. The result of squaring the product of X and Y is obtained by multiplying X and Y together and then squaring the result.