The idea is to replace "x" by its value, to replace "y" by its value, and then to do the calculations.
To simplify (\log(xy)), you can use the logarithmic property that states (\log(xy) = \log(x) + \log(y)). Given (x = 12) and (y = 20), you can calculate (\log(12) + \log(20)). If you need a numerical value, you can evaluate it using a calculator, resulting in approximately (1.0792 + 1.3010 = 2.3802) (using base 10 logarithm).
103
x+xy=8 xy=-x+8 y=-1+8/x
If ( x \neq y ), then the expression ( xy ) refers to the product of ( x ) and ( y ). The statement that ( xy \neq yx ) is generally false because multiplication is commutative; thus, ( xy = yx ) for any real numbers ( x ) and ( y ). Therefore, the condition given does not hold true for multiplication.
That is irrelevant, there is not possible way y=xy, and there is no possible way xy=x.
xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y
To simplify (\log(xy)), you can use the logarithmic property that states (\log(xy) = \log(x) + \log(y)). Given (x = 12) and (y = 20), you can calculate (\log(12) + \log(20)). If you need a numerical value, you can evaluate it using a calculator, resulting in approximately (1.0792 + 1.3010 = 2.3802) (using base 10 logarithm).
103
The GCF is xy
Xy/y = x
-17
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
(x-y) + (xy - 1) = (x - 1)(y + 1)
*Hint*=xy=x mutiplied by y.
x+xy=8 xy=-x+8 y=-1+8/x
In mathematics, XY square typically refers to the square of the product of two variables, X and Y. This can be represented as (XY)^2 or X^2 * Y^2. The result of squaring the product of X and Y is obtained by multiplying X and Y together and then squaring the result.
xy = x ÷x y = 1