(x-y) + (xy - 1) = (x - 1)(y + 1)
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xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
xy + xy = 2xy
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+
xy + x + y + 1 = (x + 1)(y + 1).