Yes
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Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
Call the unknown integer x. Then, from the problem statement, x - 3/x = 26/3, or:x2 - 3 = 26x/3; or x2 - (26/3)x - 3 = 0x = 9
The answer is -16.
x2 = 3x - 2 x2 - 3x + 2 = 0 (x-1)(x-2) = 0 x=1;x=2
any multiple of 3037 such at itself or 3037 x2 etc.