200 grams/1,000 mL x 100= 20%
684 ml
add 4 parts water per part solution
make by dissolving 2g or glucose (or dextrose) in 100 ml water or by grinding one glucose tablets (4 grams/tablet; found in drugstores) in 200ml of water.
96
4.84
Let's say the total solution is 100 liters. 50 of the liters is glucose and 50 is water. We want to make the 50 glucose equal to 10% of the total solution. For that to happen, we need to make the total solution 500 liters (50 of the 500 would be a 10% solution). So we add 400 liters of water to the original 100 liter (50/50) solution. Take the total number of units and multiply by 4. Add that much in water.
To prepare a 0.5 M glucose solution in 1 liter of water, you would need to dissolve 90.08 grams of glucose in enough water to make up the total volume of 1 liter. Start by weighing out 90.08 grams of glucose, add it to a container, and then add enough water to make the total volume up to 1 liter.
A 30% glucose solution is purely glucose and water, though it is actually impossible to keep other contaminants out of it. To create a 30% solution of glucose, you take a fixed volume of water and add 30% of that value of glucose to the water. The amount of glucose is in grammes. For example, 3g of glucose would be added to 10ml of water.
This process is called osmosis. Water molecules move from an area of low solute concentration (2% glucose solution) to an area of high solute concentration (5% glucose solution) to equalize the concentration on both sides of the membrane. This results in a net flow of water from the 2% glucose solution to the 5% glucose solution.
The balloon will contain a mixture of the 10% and 5% glucose solutions. Since water can pass through but not glucose, the glucose concentration inside the balloon will decrease over time as water moves from the lower concentration in the beaker to the higher concentration in the balloon through osmosis.
To prepare a 10% glucose solution, you would mix 10 grams of glucose with enough water to make a total solution volume of 100 ml. This means the final solution would contain 10 grams of glucose and 90 ml of water.
To make a 10% glucose solution, dissolve 10g of glucose in 90mL of water. Mix well until the glucose is completely dissolved. This will give you a total volume of 100mL of 10% glucose solution.
No,5percent glucose is an isotonic solution. 0.9 percent is for NaCl.
A 1M glucose solution means that there is 1 mole of glucose dissolved in a liter of water. This concentration indicates the number of glucose molecules per unit volume of the solution.
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
To make a 1 molar solution of glucose (C6H12O6) in 1 liter of water, you would need to dissolve 180 grams of glucose. This is because the molar mass of glucose is 180 g/mol, so 1 mole of glucose weighs 180 grams.
To find the molality of a solution, you need the mass of the solvent (usually water) in kilograms and the number of moles of solute (glucose). Given that the solution is 7.80% glucose by weight, you can calculate the mass of glucose in the solution and then convert it to moles using the molar mass of glucose. From there, you can find the molality by dividing the moles of glucose by the mass of the solvent in kilograms.