This is an interesting question. Looking at complex numbers graphically, zero is at the intersection of the real and imaginary axis, so it is 0 + 0i. But if you square zero, you get zero, which is not a negative number (a pure imaginary, when squared will give a real negative number), so I'd have to say it is not imaginary.
A complex number can be a pure imaginary, or a pure real number, or a combination of the two. The form for a complex number is a + bi, where a & b can be any real numbers (so if a = 0, then the number is pure imaginary; and if b=0, then it is a real number).
No. For example the number 1+i. Pure imaginary complex numbers are of the form 0 + a*i, where a is a non-zero real number.
No. Not is x = 0 or if it an imaginary number.
An imaginary number is a square root of a negative number. Imaginary numbers have the form bi where b is a non-zero (real number) and i is the imaginary unit, defined as the square root of − 1.if we define 'imaginary numbers' as 'complex numbers having a real part as 'zero' and a non-zero imaginary part'.. 0 doesn't fit in this description. But by, convention and for theoretical symmetry , we'll have to define 'real numbers' in pretty much the same way, and hence 0 would neither be a purely imaginary number or a purely real number.Overall i would say that 0 is a real number. Imaginary numbers only involve square roots of negative numbers.http://wiki.answers.com/Is_the_zero_imaginary_number#ixzz16w9viQWx
Yes. The number 1 + i is imaginary but not pure imaginary, while 5i is pure imaginary.
A pure imaginary number is a complex number that has 0 for its real part, such as 0+7i.
No it is not.
0 is a real number because it is part of the whole, integer, and rational number family which is in the section under real numbers (not imaginary).
A complex number can be a pure imaginary, or a pure real number, or a combination of the two. The form for a complex number is a + bi, where a & b can be any real numbers (so if a = 0, then the number is pure imaginary; and if b=0, then it is a real number).
No. For example the number 1+i. Pure imaginary complex numbers are of the form 0 + a*i, where a is a non-zero real number.
If the imaginary part of z is 0, then z is simply a real number and if you multiply by 1 which is the identity in multiplication of real numbers, you of course will still have a real number with imaginary part 0
A complex number is a number of the form a + bi, where a and b are real numbers and i is the principal square root of -1. In the special case where b=0, a+0i=a. Hence every real number is also a complex number. And in the special case where a=0, we call those numbers pure imaginary numbers. Note that 0=0+0i, therefore 0 is both a real number and a pure imaginary number. Do not confuse the complex numbers with the pure imaginary numbers. Every real number is a complex number and every pure imaginary number is a complex number also.
It is 0. The number is wholly imaginary.
No. Not is x = 0 or if it an imaginary number.
i34 is the complex part of the number 0+i34. The real part is 0, so this is a purely imaginary number.
No. A complex number consists of a real part and a imaginary part. If the real part equals zero, there is only the imaginary left and you could therefor argue that it is an imaginary number (or else it would still be a complex number -with a real part=0)
An imaginary number is a square root of a negative number. Imaginary numbers have the form bi where b is a non-zero (real number) and i is the imaginary unit, defined as the square root of − 1.if we define 'imaginary numbers' as 'complex numbers having a real part as 'zero' and a non-zero imaginary part'.. 0 doesn't fit in this description. But by, convention and for theoretical symmetry , we'll have to define 'real numbers' in pretty much the same way, and hence 0 would neither be a purely imaginary number or a purely real number.Overall i would say that 0 is a real number. Imaginary numbers only involve square roots of negative numbers.http://wiki.answers.com/Is_the_zero_imaginary_number#ixzz16w9viQWx