Yes, because a zero integer is simply 0
A factor.
an integer
A nonzero integer does not have a multiplicative inverse that is also an integer. The multiplicative inverse of an integer ( n ) is ( \frac{1}{n} ), which is only an integer if ( n ) is ( 1 ) or ( -1 ). For all other nonzero integers, the result is a rational number, not an integer. Therefore, only ( 1 ) and ( -1 ) have multiplicative inverses that are integers.
The set of nonzero integers is not closed under division. This is because dividing one nonzero integer by another can result in a non-integer. For example, ( 1 \div 2 = 0.5 ), which is not an integer. Therefore, the result of the division is not guaranteed to be a member of the set of nonzero integers.
Yes.
if p is an integer and q is a nonzero integer
A factor.
A rational number is always the result of dividing an integer when the divisor is nonzero.
No.
an integer
Yes, when a nonzero integer is divided by it's opposite it's value equals -1
Yes, it is.
Yes.
Choose a nonzero integer for n to show -n can be evaluated as a positive number?
Any integer divided by a non-zero integer is rational.
There is none. An integer has to be a number with no decimal places
Divide a non-zero integer by a non-zero integer.