No, not necessarily. In theory you can assign different names to variables, and it doesn't always follow that they are alphabetical. So a divided by b could be x or t or n or any letter you like. Equally, you could use different letters in the initial calculation resulting in c, so x divided by y could be c. Having said that, letters used are commonly used in sequence, so a divided by b = c would be common. Having a, b and c together or x, y and z together is common. In certain situations though, certain letters are given special designations as in the famous E = mc² equation.
Because there is no way to define the divisors, the equations cannot be evaluated.
To determine what A, B, and C can be divided by, we need to know the specific values of A, B, and C. Generally, any integer can be divided by 1 and itself, and if they share common factors, they can also be divided by those factors. For example, if A, B, and C are all even numbers, they can be divided by 2. Additionally, if they are all multiples of a certain number, they can be divided by that number as well.
b divided by 2
I think I know how to do this but I'm not sure...It's something like:A, B & C are consecutive so:A=A, B=A+/-1, C=A+/-2So:A/(A+/-1)/(A+/-2)=0.3I think it can be worked out from there but I'm not sure how...
No it is not a, b, c or d.
Because there is no way to define the divisors, the equations cannot be evaluated.
To determine what A, B, and C can be divided by, we need to know the specific values of A, B, and C. Generally, any integer can be divided by 1 and itself, and if they share common factors, they can also be divided by those factors. For example, if A, B, and C are all even numbers, they can be divided by 2. Additionally, if they are all multiples of a certain number, they can be divided by that number as well.
b divided by 2
67 plus 13 = 80 80 divided by 8 = 10
I think I know how to do this but I'm not sure...It's something like:A, B & C are consecutive so:A=A, B=A+/-1, C=A+/-2So:A/(A+/-1)/(A+/-2)=0.3I think it can be worked out from there but I'm not sure how...
You add 2 fractions with the same denominator [c], so the sum is the sum of the numerators divided by the denominator: a/c + b/c = (a+b)/c
No it is not a, b, c or d.
No. is it not a, b,c, or d.
2: if a*b=c, then (1) c/a = b and (2) c/b = a hope this answers your question
AB/8Cas divided by 8/A can be reversed to multiplied by A/8so B/C x A/8 = AB/8CExample: If A=4 B=6 C=3then 6/3 divided by 8/4 = 2/2 = 1also AB/8C = 24/24 = 1Q.E.D.
yes
take a/b divided by c/d, this is the same as a/b X d/c So you multiply by the reciprocal