Yes. Any integer whose last digit is 1, 3, 5, 7, or 9, is odd. Others (those ending with 2, 4, 6, 8, or 0) are even. (The actual definition is that an even number is one that is divisible by 2, an odd number is not.)
yes 1 is is odd a number
The number 1 is an odd number.
An odd number multiplied by another odd number will always equal an odd number. Therefore odd2 = odd x odd = odd number. eg 32 = 3 x 3 = 9. Take away 1 and you will have on even number.
odd
no physically you cannot because before an odd number is a even number.
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.
Answer:1 is an odd number If you need to learn math go to the web site in the link below
No. The sum of 1 odd number and 1 even number must always be odd.
199 The first odd number is 1 The second odd number is 3 The rth odd number is thus 2r - 1 Thus the 100th odd number is 2 x 100 - 1 = 199.
The smallest odd number is 1.
The nth odd number is 2n - 1 So 102nd odd number is 2*102 - 1 = 204 - 1 = 203
799 would be the 400th odd number even if '1' were not the first one.
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 1 is an odd number.
Any even number can be written in the form 2n for some natural number n.Any odd number can be written as 2n+1 for a natural number nNow add an even to an odd.2n+2n+1=4n+1 which is 2(2n)+1 and this is the form for an odd number.
1st odd number . . . 1 (1 less than double 1)2nd odd number . . . 3 (1 less than double 2)3rd odd number . . . 5 (1 less than double 3)4th odd number . . . 7 (1 less than double 4)5th odd number . . . 9 (1 less than double 5)Are you seeing a pattern yet ?6th odd number . . . 11 (1 less than double 6)7th odd number . . . 13 (1 less than double 7)...Qth odd number . . . . (1 less than double Q)
1st odd number . . . 1 (1 less than double 1)2nd odd number . . . 3 (1 less than double 2)3rd odd number . . . 5 (1 less than double 3)4th odd number . . . 7 (1 less than double 4)5th odd number . . . 9 (1 less than double 5)Are you seeing a pattern yet ?6th odd number . . . 11 (1 less than double 6)7th odd number . . . 13 (1 less than double 7)...Qth odd number . . . . (1 less than double Q)
It is odd. The definition of an odd number is "a number a is odd if there exists an integer n such that a = 2n + 1." Let a = 1 and let n = 0, so 1 = (2x0) + 1.