It may be or may not be; however a normal distribution is unimodal.
No, the normal distribution is strictly unimodal.
Your distribution is unimodal and symmetrical.
Please consider the probability density function graphs for the beta distribution, given in the link. For alpha=beta=2, the density is unimodal, which is to say, it has a single maximum. In contrast, for alpha=beta=0.5, the density is bimodal; it has two maxima.
Yes. When we refer to the normal distribution, we are referring to a probability distribution. When we specify the equation of a continuous distribution, such as the normal distribution, we refer to the equation as a probability density function.
No. Normal distribution is a continuous probability.
No, the normal distribution is strictly unimodal.
No. Normal distribution is a special case of distribution.
Yes it is.
No they are not the same in a unimodal symmetrical distribution and they will never be
The median and mode.
Your distribution is unimodal and symmetrical.
No, it is in general not true - for example for uniform distribution on [0,1] every number in the interval is a mode, but the mean is 1/2. The correct answer would be that a symmetric unimodal distribution has one mode equal to the mean (but may have modes elsewhere).
Bell-shaped, unimodal, symmetric
If the distribution is not symmetric, the mean will be different from the median. A negatively skewed distribution will have a mean hat is smaller than the median, provided it is unimodal.
Please consider the probability density function graphs for the beta distribution, given in the link. For alpha=beta=2, the density is unimodal, which is to say, it has a single maximum. In contrast, for alpha=beta=0.5, the density is bimodal; it has two maxima.
Unimodal is having a normal disturbution. The mean, median, and mode are all a the center. When looking at a graph, there is one maximum.
The standard normal distribution is a normal distribution with mean 0 and variance 1.