It is not necessary that all symetric distribution may be normal.
I think yes or no
No. The binomial distribution (discrete) or uniform distribution (discrete or continuous) are symmetrical but they are not normal. There are others.
No. The Normal distribution is symmetric: skewness = 0.
If the two distributions can be assumed to follow Gaussian (Normal) distributions then Fisher's F-test is the most powerful test. If the data are at least ordinal, then you can use the Kolmogorov-Smirnov two-sample test.
It may be or may not be; however a normal distribution is unimodal.
Yes it is.
No, not all distributions are symmetrical, and not all distributions have a single peak.
No. There are many other distributions, including discrete ones, that are symmetrical.
No, the normal distribution is strictly unimodal.
Unimodal is having a normal disturbution. The mean, median, and mode are all a the center. When looking at a graph, there is one maximum.
It is not necessary that all symetric distribution may be normal.
Bell-shaped, unimodal, symmetric
Don't know what "this" is, but all symmetric distributions are not normal. There are many distributions, discrete and continuous that are not normal. The uniform or binomial distributions are examples of discrete symmetric distibutions that are not normal. The uniform and the beta distribution with equal parameters are examples of a continuous distribution that is not normal. The uniform distribution can be discrete or continuous.
The three are different measures of central tendency. None of them are substitutes for the other and, except in symmetric unimodal distributions, none of them can be used to estimate another.
I think yes or no
About half the time.