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What is the formula of vertical velocity?
vf=vi+at or vf2=vi2+2ad where a=-9.8m/s2
Factor this expression 4ac plus 2ad plus 2bc plus bd?
4ac + 2ad + 2bc +bd = 2a*(2c + d) + b*(2c + d) = (2c + d)*(2a + b)
How is acceleration related to the distance and time elapsed?
acceleration cannot be calculated from these values alone unless one makes a few assumptions: Vf=final velocity Vi=initial velocity a=acceleration d=displacement t=time assume Vi=0 (Vf-Vi)/t=a Vf=at+Vi Vf**2=Vi**2+2ad (at)**2=2ad aatt=2ad att=2d a=2d/t**2
Factor 4ac plus 2ad plus 2bc plus bd?
(2a + b)(2c + d)
How many years were there between 5 BC and 5 AD?
All of each of 5BC, 4BC, 3BC, 2BC, 1BC, 1AD, 2AD, 3AD, 4AD, so 9 Or, you might mean 4BC ........... 4AD so 8
How many years is 2AD this year?
2 AD
Is it true that Saint Stephen was born in 2AD?
We do not know when Stephen was born but it would have been in the early first century. AD2 would be a close guess.
Factor this expression check by multiplying factors.4ac plus 2ad plus 2bc plus 4bd?
ac + 2ad + 2bc + 4bd = a(c + 2d) + 2b(c + 2d) = (a + 2b)(c + 2d) Now expand to confirm your answer: c(a + 2b) + 2d(a + 2b) = ac + 2bc + 2ad + 4bd ≡ ac + 2ad + 2bc + 4bd
Factoring by grouping ac plus 2ad plus 2bc plus 4bd?
ac + 2ad + 2bc + 4bd (ac + 2ad) + (2bc + 4bd) group the figures a(c + 2d) + 2b(c + 2d) remove the common divisors of each set (a + 2b)(c + 2d) take the figures in parentheses as one set, and add the outside figures as the other
What does 4ac 2ad 2bc bd factor into?
(2a + b)(2c + d)
Who created the first model of planetary motion?
Ptolemy created the Geocentric model in 2AD
What is the formula of vertical velocity?
vf=vi+at or vf2=vi2+2ad where a=-9.8m/s2
Factor this expression 4ac plus 2ad plus 2bc plus bd?
4ac + 2ad + 2bc +bd = 2a*(2c + d) + b*(2c + d) = (2c + d)*(2a + b)
What is the correct formula manipulation to find acceleration when using the equation vf2 vi2 2ad?
To find acceleration using the equation vf^2 = vi^2 + 2ad, you can rearrange the formula to isolate 'a'. First, subtract vi^2 from both sides to get vf^2 - vi^2 = 2ad. Then, divide both sides by 2d to solve for acceleration: a = (vf^2 - vi^2) / (2d).
How to find out the velocity when acceleration and distance is given?
The equation that does involve time is.. v² = v₀² + 2ad
How is acceleration related to the distance and time elapsed?
acceleration cannot be calculated from these values alone unless one makes a few assumptions: Vf=final velocity Vi=initial velocity a=acceleration d=displacement t=time assume Vi=0 (Vf-Vi)/t=a Vf=at+Vi Vf**2=Vi**2+2ad (at)**2=2ad aatt=2ad att=2d a=2d/t**2
How do you factor this expression ac plus 2ad plus 2bc plus 4bd?
(a + 2b)(c + 2d)
