6 = p - 17 + 1-------------------5 = p - 17-------------------p = 22
22
To cube something is to raise to the third power. P cubed would be p^3
17 syllables in a haiku poem
If: -17 = 6p-5 Then: p = -2
p(one) = 1/6 p(not one) = 5/6 p(at least one) = 1 - p(failure) p(failure) = (4C0)(5/6)^4 = 1 x 625/1,296 = 0.48 p(at least one) = 1 - 0.48 = 0.52
Get contacts. :P
6 = p - 17 + 1-------------------5 = p - 17-------------------p = 22
17 S in a H P
22
alebraic expression! :p
At least one son who was born in 1994.
-4(3 - p) > 5(p + 1) => -12 + 4p > 5p + 5-17 > p, that is p < -17.
There is one s orbital and three p orbitals and five d orbitals in the third energy level.
17 is a prime number
The probability of tossing a coin 9 times and getting at least one tail is: P(9 times, at least 1 tail) = 1 - P(9 heads) = 1 - (0.50)9 = 0.9980... ≈ 99.8%
Ah, what a happy little math problem we have here! When you see "p times p to the third power," you simply need to multiply p by p cubed. This gives you p to the power of 4, as you add the exponents when you multiply like bases. Just a joyful reminder to embrace mistakes as happy little accidents in your math journey!