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one-third of p is at least -17

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14y ago

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If a fair six sided die was rolled 4 times what is the probability of getting at least one ace one?

p(one) = 1/6 p(not one) = 5/6 p(at least one) = 1 - p(failure) p(failure) = (4C0)(5/6)^4 = 1 x 625/1,296 = 0.48 p(at least one) = 1 - 0.48 = 0.52


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Can you answer this 6 equals p-17 plus 1?

6 = p - 17 + 1-------------------5 = p - 17-------------------p = 22


How do you write the algebraic expression for 2 less than one third of the points that the Panthers scored?

To write the algebraic expression for "2 less than one third of the points that the Panthers scored," first let ( P ) represent the points scored by the Panthers. One third of the points is expressed as ( \frac{1}{3}P ). Therefore, "2 less than one third of the points" can be written as ( \frac{1}{3}P - 2 ).


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17 S in a H P


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What is 5 less than a number p is -17 as an equation?

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How do you solve -4(3-p) and gt5(p plus 1)?

-4(3 - p) > 5(p + 1) => -12 + 4p > 5p + 5-17 > p, that is p < -17.


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What is the probability of tossing a coin 9 times and getting at least one tail?

The probability of tossing a coin 9 times and getting at least one tail is: P(9 times, at least 1 tail) = 1 - P(9 heads) = 1 - (0.50)9 = 0.9980... ≈ 99.8%


17 is a P N?

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A coin is flipped 3 times. What is the probability of getting at least 1 tails?

7/8 P(all heads) = (1/2)*(1/2)*(1/2)=(1/8). P(at least one tails) = 1-P(all heads) = 7/8. Another (more time-consuming) way to get the same result: P(all tails) = (1/2)^3=1/8 P(exactly two tails) = 3*(1/2)^3=3/8 P(exactly one tails) = 3*(1/2)^3=3/8 P(at least one tail) = P(all tails) + P(exactly two tails) + P(exactly one tails) = 7/8