Using Pythagoras' theorem its length is square root of 203
Area: 11 Times Square root of 203 = 11 times sq rt 203
Perimeter: 2(11+sq rt 203) = 22+2 times sq rt 203
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
6x-14
The diagonal is 26cm
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
You divide the perimeter by the width and you get the lenght
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
You CAN'T calculate the perimeter of a rectangle, knowing only its diagonal. You do need some additional information about the rectangle - such as its width, or its length, or perhaps the length/width ratio.
The perimeter would be 28 meters.
The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.
It depends on whether you want the width as a fraction of the length or perimeter or something else - like the diagonal.
6x-14
The width will be 30cm
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
The diagonal is 26cm