If you are packing items into a box, you can use square roots along with Pythagorean theorem to help determine if a smaller box could work with items packed diagonally.
Use Pythagoras' theorem to find the length of the outer diagonal and then use this as the base for the inner diagonal (the longest length of the cube) 82+82 = 128 and the square root of this is 11.3137085 cm 11.31370852+82 = 192 and the square root of this is 13.85640646 cm The longest pencil is 13.85640646 or just under 14 cm
A box is a 3-dimensional object and only two measures are given so it is not clear what the question means. Across the base of the box, the diagonal is 10*sqrt(2) = 14.142 approx.
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
The long diagonal will be sqrt(7500) cm = 86.60 cm (to 2 dp)
Let's denote the height, length, and width of the box as h, l, and w respectively. We can use the Pythagorean Theorem, which states that the square of the length of the diagonal equals the sum of the squares of the other two sides. So, for this box, we have ( h^2 + l^2 + w^2 = 14^2 ) and an additional constraint that the box is rectangular, not a cube. Without more information, we cannot uniquely determine the dimensions, but we know that there are infinite possible combinations of h, l, and w that satisfy the given conditions.
If you are packing items into a box, you can use square roots along with Pythagorean theorem to help determine if a smaller box could work with items packed diagonally.
13 ft (hint: use Pythagorean Theorem twice)
The longest ski pole to fit would lie diagonally. The length of the diagonal can be found by the pythagorean theorem.d=sqrt(1202+252)d ~= 122.58 cm
It has to land in the opposite diagonal service box (because you face the opposite diagonal service box when you are serving).
If it is a 2-D box then 70.71
Use Pythagoras' theorem to find the length of the outer diagonal and then use this as the base for the inner diagonal (the longest length of the cube) 82+82 = 128 and the square root of this is 11.3137085 cm 11.31370852+82 = 192 and the square root of this is 13.85640646 cm The longest pencil is 13.85640646 or just under 14 cm
A box is a 3-dimensional object and only two measures are given so it is not clear what the question means. Across the base of the box, the diagonal is 10*sqrt(2) = 14.142 approx.
An out of box solution refers to a solution that works straight out of the box. It means that the solution is ready to use and will work as soon as you have it.
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
The long diagonal will be sqrt(7500) cm = 86.60 cm (to 2 dp)