Using Pythagoras: 10 times square root of 2 feet
The base is 24 cm x 18 cm. By Pythagoras, the diagonal of the base is sqrt(242 + 182) = sqrt(576 + 324) = sqrt(900) = 30 cm
A 9 x 12 rectangle has a diagonal of 15.
A box has no equation. There are different equations for its volume, its surface area, the longest (principal) diagonal.
Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 20 × √2 ≈ 28.3 units
If it is a 2-D box then 70.71
36
If diagonal is 10 then each side is sqrt 50 (Pythagoras) and area is sqrt 50 x sqrt 50 ie 50
10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet
The diagonal of 132 x 132 is: 186.7
Using Pythagoras: 10 times square root of 2 feet
The base is 24 cm x 18 cm. By Pythagoras, the diagonal of the base is sqrt(242 + 182) = sqrt(576 + 324) = sqrt(900) = 30 cm
A 9 x 12 rectangle has a diagonal of 15.
If the diagonal is 10 we know all sides are equal so from pythagoraen theorem each side is 7.07 inch length Area = 7.07 x 7.07 = 50
The radius of a square is the radius of the circumcircle, ie the distance from the centre of the square to any vertex, which is half the length of the diagonal of the square. Using Pythagoras: diagonal^2 = side^2 + side^2 → diagonal = √(2 x side^2) area = side^2 → diagonal = √(2 x area) radius = 1/2 x diagonal = 1/2 x √(2 x area) → radius = 1/2 x √(2 x 72 sq in) = 1/2 x √(144 sq in) = 1/2 x 12 in = 6 in.
A small box , 10 x 10 x 10 centimetres.
The diagonal of a 30' x 30' square is: 42.43 feet.