4
You cannot solve one linear equation in two variables. You need two equations that are independent.
y = mx + c m = slope = rise/run c = y intercpt
You cant solve it unless it is an equation. To be an equation it must have an equals sign.
Quite simply, the latter is a group of the former.A system of linear equations is several linear equations taken together, each using the same group of unknowns. Usually, such a system provides one linear equation for each unknown (x, y, z, et al) that must be found (more complex systems can exist, though). You can use and manipulate these linear equations as you would a single linear equation to help solve for the unknowns. One way is to reduce all but one of the unknowns so that each can be expressed in terms of the remaining unknown and then solve for the remaining unknown which would in turn give you the others.
Addition and subtraction are inverse operations. So you can solve addition by subtracting.
you cant
If it is a linear function, it is quite easy to solve the equation explicitly, using standard methods of equation-solving. For example, if you have "y" as a function of "x", you would have to solve the variable for "x".
The answer depends on whether they are linear, non-linear, differential or other types of equations.
4
You cannot solve one linear equation in two variables. You need two equations that are independent.
y = mx + c m = slope = rise/run c = y intercpt
There are no disadvantages. There are three main ways to solve linear equations which are: substitution, graphing, and elimination. The method that is most appropriate can be found by looking at the equation.
For a linear I can see no advantage in the table method.
You cant solve it unless it is an equation. To be an equation it must have an equals sign.
Quite simply, the latter is a group of the former.A system of linear equations is several linear equations taken together, each using the same group of unknowns. Usually, such a system provides one linear equation for each unknown (x, y, z, et al) that must be found (more complex systems can exist, though). You can use and manipulate these linear equations as you would a single linear equation to help solve for the unknowns. One way is to reduce all but one of the unknowns so that each can be expressed in terms of the remaining unknown and then solve for the remaining unknown which would in turn give you the others.
Use a variable to represent the unknown. 'Translate' the words to math symbols and write an equation to solve. Solve the equation. Check.