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what you have here is the equation for a "porabola" which is pretty much an arch which can be graphed on a number plane with an x and y axis. in this case the porabola cuts the x axis at 4,5 the y axis at 20 and has a vertex of (4.5,-0.25)
y = x2 + 3 Since the x term is missing, the x-coordinate of the vertex is 0. If x = 0, then y = 3. Thus, (0, 3) is the vertex, the minimum point of the parabola.
The vertex is at the point (0, 4).
(0, -3)
No.
what you have here is the equation for a "porabola" which is pretty much an arch which can be graphed on a number plane with an x and y axis. in this case the porabola cuts the x axis at 4,5 the y axis at 20 and has a vertex of (4.5,-0.25)
y = x2 + 3 Since the x term is missing, the x-coordinate of the vertex is 0. If x = 0, then y = 3. Thus, (0, 3) is the vertex, the minimum point of the parabola.
A vertex is a quadralateral edge, with the hypotenuse of pi 8 squared. it has 12 dimensions.
The vertex is at the point (0, 4).
(0, -3)
No.
8
Need signs between terms.
(-3, -5)
The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5. The coefficient of the squared term in the parabola's equation is -3.
The vertex of this parabola is at -3 -1 When the y-value is 0 the x-value is 4. The coefficient of the squared term in the parabolas equation is 7
The vertex of this parabola is at 5 5 When the x-value is 6 the y-value is -1. The coefficient of the squared expression in the parabola's equation is -6.