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5x2 + x - 4 = 0

a = 5, b = 1, c = -4

The equation of the axis of the symmetry of a parabola is x = - b/2a, which also is the x-coordinate of the vertex.

x = - b/2a = - 1/2

Find the y-coordinate:

f(x) = 5x2 + x - 4

f(-1/2) = 5(-1/2)2 + (-1/2) - 4 = 5(1/4) - 1/2 - 4 = 5/4 - 1/2 - 4 = 4/2 - 4 = 2 - 4 = -2

Thus, the vertex is (-1/2, -2).

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Q: Vertex of 5x2 plus x-4 equals 0?
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