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5x2 + x - 4 = 0
a = 5, b = 1, c = -4
The equation of the axis of the symmetry of a parabola is x = - b/2a, which also is the x-coordinate of the vertex.
x = - b/2a = - 1/2
Find the y-coordinate:
f(x) = 5x2 + x - 4
f(-1/2) = 5(-1/2)2 + (-1/2) - 4 = 5(1/4) - 1/2 - 4 = 5/4 - 1/2 - 4 = 4/2 - 4 = 2 - 4 = -2
Thus, the vertex is (-1/2, -2).
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