5x2 + x - 4 = 0
a = 5, b = 1, c = -4
The equation of the axis of the symmetry of a parabola is x = - b/2a, which also is the x-coordinate of the vertex.
x = - b/2a = - 1/2
Find the y-coordinate:
f(x) = 5x2 + x - 4
f(-1/2) = 5(-1/2)2 + (-1/2) - 4 = 5(1/4) - 1/2 - 4 = 5/4 - 1/2 - 4 = 4/2 - 4 = 2 - 4 = -2
Thus, the vertex is (-1/2, -2).
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Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
If you mean: f(x) = x4 - 3x3 + 5x2 / x2 then: f(x) = x4 - 3x3 + 5 ∴ f'(x) = 4x3 - 9x2 If you mean: f(x) = (x4 - 3x3 + 5x2) / x2 then: f(x) = x2 - 3x + 5 ∴ f'(x) = 2x - 3
No.
x4 + 7x2 - 60 = x4 + 12x2 - 5x2 - 60 = x2(x2 + 12) - 5(x2 +12) = (x2 - 5)(x2 +12)
I assume you meant x^4 + 5x^2 +10x + 12. The remainder is 28