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4
5 - a - 1 + c - 6a2 + a2
x = cx = aa+1 If x = cx, then c = 1 aa = a2 if a2 + 1 = x, then a2 = x-1 short of parametrization, this is the answer for this equation, but if you doing advanced maths, then let x= t (teR) a2 = -1 +t (teR)
A1 + A2 = 90 A1 = 4*A2 Substituting from the second equation into the first: 4*A2 + A2 = 90 or 5*A2 = 90 so that A2 = 18 and then, by the second equations, A1 = 4*18 = 72
If you are given the length of 1 leg, L, and the altitude, A, the length of the base is the 2x square root of (L2 -A2 )