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(-1, 2)
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what- given a preimage A(a, -3)?
(3, 2)
Find an equation of the line containing the given point and having the given slope 3-6m1?
Assuming the point is (3, -6) and the slope 1, the equation is x - y - 9 = 0
A line connecting 2 1 to another point has a slop of 3 what is closest point with whole number coordinates above 2 1?
slope = change_in_y / change_in_x → change_in_y = slope × change_in_x The first point with a whole number for the x-coordinate above (2, 1) will have an x-coordinate of 3 = 2 + 1 → change_in_x = 1 → change_in_y = 3×1 = 3 → new y = 1 + 3 = 4 → The first point above (2, 1) with whole number coordinates on the given line is (3, 4).
Which is the equation of the line 3 1 and 0 0?
I assume that is a straight line between point (0, 0) and point (3, 1): The equation of any line is given by: y - yo = m(x - xo) where m is the gradient given by: m = (y1 - yo)/(x1 - x0) Thus, line is: y - 0 = (1 - 0)/(3 - 0)(x - 0) ⇒ y = 1/3 x or 3y = x
What is the equation in slope-intercept form of the line that has a slope of -3 and contains the point 1 and1?
Assuming that the point is located at (1,1) then the equation is: y = -3x + 4 We know this by multiplying the slope by the x of the point given, and finding the difference between this value, and the y value of the point. 1 - (-3) is 4, hence the +4 in our equation.
what- given a preimage A(a, -3)?
(3, 2)
How do you describe the location of the given points?
Describe the location of the given points. (1 point each)1. (1, 4, -2) 2. (-2, -1, 3)
Find an equation of the line containing the given point and having the given slope 3-6m1?
Assuming the point is (3, -6) and the slope 1, the equation is x - y - 9 = 0
A line connecting 2 1 to another point has a slop of 3 what is closest point with whole number coordinates above 2 1?
slope = change_in_y / change_in_x → change_in_y = slope × change_in_x The first point with a whole number for the x-coordinate above (2, 1) will have an x-coordinate of 3 = 2 + 1 → change_in_x = 1 → change_in_y = 3×1 = 3 → new y = 1 + 3 = 4 → The first point above (2, 1) with whole number coordinates on the given line is (3, 4).
Which is the equation of the line 3 1 and 0 0?
I assume that is a straight line between point (0, 0) and point (3, 1): The equation of any line is given by: y - yo = m(x - xo) where m is the gradient given by: m = (y1 - yo)/(x1 - x0) Thus, line is: y - 0 = (1 - 0)/(3 - 0)(x - 0) ⇒ y = 1/3 x or 3y = x
Find an equation of the line having the given slope and containing the given point m equals 2 over 3 and 2 and -1?
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7
A set of points that are ALL THE same distance from a given point?
The set of all points a given distance from a center point is a circle. The given distance is the radius, and the given point is the center. Or, in 3 dimensional space, a sphere.
What does writing an equation in slope form of the line that passes through the given point mean?
p (2,-1) and slope 3
What is the equation in slope-intercept form of the line that has a slope of -3 and contains the point 1 and1?
Assuming that the point is located at (1,1) then the equation is: y = -3x + 4 We know this by multiplying the slope by the x of the point given, and finding the difference between this value, and the y value of the point. 1 - (-3) is 4, hence the +4 in our equation.
What is slope of curve at point where equation is y is equal to 10 of x at 1 comma 3 Coordinates?
The point with the given coordinates does not lie on the curve and so the question makes no sense.
What is the set of all points a given distance from a fixed point?
The set of all points a given distance from a center point is a circle. The given distance is the radius, and the given point is the center. In 3 dimensional space, the set would be the surface of a sphere.
Can you find the point of 4 and -3 in point slope form that has a slope of 1?
Using the point (x1, y1) = (4, -3) and the slope m = 1, we have: (y - y1) = m(x - x1) substitute the given values: (y - -3) = 1(x - 4) (y + 3) = (x - 4) this is the point-slope form of the equation of a line. y + 3 = x - 4 subtract 3 to both sides y = x - 7 this is the slope intercept form, and -x + y = -7 is the general form
