Q: What is 2x < 2?

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-2x - 2 = 4-2x = 4 + 2-2x = 6x = 6/-2x = -3Check:-2(-3) - 2 = 46 - 2 = 44 = 4

2x + 4 = 2 2x = -2 x = -1

2x-2 = 10 2x= 10+2 2x=12 x= 12/2 x=6

Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C

- 2X - 2 = 4 ?If so.....,- 2X - 2 = 4add 2 to each side- 2X = 6divide each sides integers by - 2X = - 3==========check- 2(- 3) - 2 = 46 - 2 = 44 = 4-------------checks

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-2x - 2 = 4-2x = 4 + 2-2x = 6x = 6/-2x = -3Check:-2(-3) - 2 = 46 - 2 = 44 = 4

2x + 4 = 2 2x = -2 x = -1

2x-2 = 10 2x= 10+2 2x=12 x= 12/2 x=6

Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C

Here is how you solve this problem... 5x*4-3x*5*2x-9= (Combine like-terms) 5x-3x*2x= 2x*2x=(2x)2 (Add the rest of the problem) (2x)2*4*5-9=(2x)2*20-9 (2x)2*11 (2x)2 *11= your answer

-2x-2x-2x-2= 16 (positive)

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Integral of 2x dx /(2x-2) Let 2x=u 2 dx = du dx = (1/2) du Integral of 2x dx /(2x-2) = Integral of (1/2) u du / (u-2) = Integral of 1/2 [ (u-2+2) / (u-2)] dx = Integral of 1/2 [ 1+ 2/(u-2)] dx = u/2 + (1/2) 2 ln(u-2) + C = u/2 + ln(u-2) + C = (2x/2) + ln(2x-2) + C = x + ln(2x-2) + C