Let the side length of the square be ( s ). The area of the square is ( s^2 ). The rectangle has a length of ( s + 5 ) and a width of ( \frac{s}{2} ), giving it an area of ( (s + 5) \cdot \frac{s}{2} ). The equation that describes the situation where the areas are equal is ( s^2 = \frac{s(s + 5)}{2} ).
2(x + y) = 156 x = 2y Here x = length of rectangle and y = width
area of the rectangle..
A ruler can be very helpful in that situation.
By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.
The area of rectangle is : 896.0
2(x + y) = 156 x = 2y Here x = length of rectangle and y = width
area of the rectangle..
The base equation for calculating the area of a rectangle is length multiplied by width.
length * width
A ruler can be very helpful in that situation.
If you do not know the length or breadth of a rectangle, you cannot know the area. If you do not know the area of a rectangle, you cannot know the length and breadth. To know the length and breadth of a rectangle, you have to know some other contributing factor in the equation. If you don't, measure it!
There is no "height" of a rectangle, unless it's a rectangular prism. Do you mean the length? If you have the area of the rectangle, the equation should be:A= L x WPlug in the area and the length and solve for the width, or plug in the area the width of the rectangle, and solve for the length.
By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.
The equation for a rectangle is h(height) x w(width) = area . By manipulating the equation we can show that width=area/length. So 132/12=11. This means the width of the rectangle is 11.
The area of rectangle is : 896.0
you must know the length of the rectangle as well in order to fill in the equation A=lengthxWidth
The equation is: 4W-3 = L