To get the 2s complement, find the 1s complement (by inverting the bits) and add 1. Assuming that number is [4-bit] binary it would be 1000. If it is preceded by 0s, as in, for example, 0000 1000, then it would be 1111 1000.
I think 7x3 is = to 21
(1234)hex=(0001 0010 0011 0100)2 (DA57)hex=(1101 1010 0101 0111)2 Taking, (1234)hex=(0001 0010 0011 0100)2 =(1110 1101 1100 1011) -1s complement =(1110 1101 1100 1100) -2s complement Now ,add 2s complement of (1234)hex with (DA57)hex, we get 1110 1101 1100 1100 + 1101 1010 0101 0111 1 1100 1000 0010 0011 There is a Carry bit Since,carry is generated.so,no is negative Then take 2s complement of above no.Thus ,we get 0011 0111 1101 1101=(37DD)hex (1234)hex -(DA57)hex =37DD)hex
-15 is 11111111 and 2s com is 1111 0001
-123 = 11 1000 0101 [I presume the number 123 is in decimal] First write the positive number in binary using 10 bits (I've split it into groups of 4 bits to make it easier to read): 123 = 00 0111 1011 Convert to 1s complement by inverting all bits (any 0 => 1, any 1 => 0): 00 0111 1011 => 11 1000 0100 Finally add 1 to get 2s complement: 11 1000 0100 + 1 = 11 1000 0101 Thus the 2s complement of the negative number: -123 = 11 1000 0101 This can also be expressed in hexadecimal: -123 = 0x385 Or in octal (easy to convert if the binary number is first written in groups of 3 bits): -123 = 1 110 000 101 = 01605 [I've used C notation for the hexadecimal and octal numbers.]
8-bit 2s complement representation of -19 is 11101101 For 1s complement invert all the bits. For 2s complement add 1 to the 1s complement: With 8-bits: 19 � 0001 0011 1s � 1110 1100 2s � 1110 1100 + 1 = 1110 1101
1s + 1s + 1 = 2s + 1
The 2s orbital is larger than the 1s orbital and is higher in energy.
Binary numbers, with or without a computer are a series of 1's and 0's.
the 1s orbital is closer to the nucleus and has a lower energy level compared to the 2s orbital. Additionally, the 2s orbital has a slightly higher energy, larger size, and can hold more electrons than the 1s orbital.
To get the 2s complement, find the 1s complement (by inverting the bits) and add 1. Assuming that number is [4-bit] binary it would be 1000. If it is preceded by 0s, as in, for example, 0000 1000, then it would be 1111 1000.
1s 2s 3s 3p 4s 3d 4p
lithium atom is just a ball it has 1s and 2s orbitals both of which are spheres the 1s is occupied by two electrons and the 2s one electron
To find the 2s complement, invert all the bits (to get the 1s complement) and add 1: 10001100 00111001 → 01110011 11000110 + 1 = 01110011 11000111 If you have an operator missing between the two numbers then if it is subtract: 10001100 - 00111001 = 10001100 + 11000111 = carry set & 01010011 & overflow set. If not subtract but some other operator, please re-ask your question with the operator written out as a word.
The ground state configuration of 1s²2s²2p²3s²3p¹ is [Ne]3s²3p¹. This notation represents the electron configuration in shorthand form, where [Ne] represents the electron configuration of the noble gas neon (1s²2s²2p⁶).
The electron configuration for lithium is 1s^2 2s^1. This means that lithium has 3 electrons, with two in the 1s orbital and one in the 2s orbital.
In a silicon atom, there are four filled orbitals. Specifically, there are two filled in the 1s orbital and two filled in the 2s orbital.