When a straight line equation is parallel to another equation the slope remains the same but the y intercept changes
yea!
The equation of the line can be written as y = mx + b, where m is the slope and b is the y-intercept. Given that the slope is 3 and the y-intercept is (0, -10), the equation of the line is y = 3x - 10.
y = 7x-10
15
The equation of a horizontal line is of the form y=k, where k is the y-coordinate of the point through which the line passes. Therefore, the equation of the horizontal line through the point (8, -10) is y = -10.
When a straight line equation is parallel to another equation the slope remains the same but the y intercept changes
yea!
The equation of the line can be written as y = mx + b, where m is the slope and b is the y-intercept. Given that the slope is 3 and the y-intercept is (0, -10), the equation of the line is y = 3x - 10.
y = 7x-10
15
10
If 10 and 12 are the x and y coodinates then the straight line equation is: y = 0.83x+3.7
The equation is: y = 4x-22
What is the equation of the line containing the points (5, 2), (10, 4), and (15, 6)?y = (2/5)x
Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation. But if you mean 4x+y = 10 then y = -4x+10 and the parallel equation is y = -4x+6
7x + 10y = 4.5 : 10y = -7x + 4.5 : y = -x.7/10 + 0.45, the gradient of this line is -7/10 Two straight lines are perpendicular if the product of their gradients is -1. Let the equation for the perpendicular line be y = mx + c Then m x -7/10 = -1 : m = 10/7 The equation for the perpendicular line is y = x.10/7 + c If the values of x and y for the point of intersection are provided then these can be substituted in the perpendicular line equation and the value of c obtained. If appropriate, the equation can then be restructured to a format similar to the original equation.